Calculating the Volume of a Bubble at Different Depths in the Sea

  • Thread starter Thread starter zcabral
  • Start date Start date
  • Tags Tags
    Bubble Volume
AI Thread Summary
To calculate the volume of an air bubble exhaled by a diver at a depth of 24.0 m, it's essential to consider both temperature and pressure changes as the bubble rises. The relevant equation is P1V1/T1 = P2V2/T2, where pressure must account for hydrostatic pressure at depth plus atmospheric pressure. The hydrostatic pressure can be calculated using the formula P = density x g x depth, with the density of seawater at 1025 kg/m3. It is crucial to use absolute temperatures in Kelvin for accurate calculations. The pressure just before the bubble breaks the surface is approximately 1 atm, plus the pressure from the water column above it.
zcabral
Messages
30
Reaction score
0

Homework Statement



At 24.0 m below the surface of the sea (density = 1025 kg/m3), where the temperature is 5.00°C, a diver exhales an air bubble having a volume of 1.20 cm3. If the surface temperature of the sea is 20.0°C, what is the volume of the bubble just before it breaks the surface?
cm^3

Homework Equations



P1V1/T1=P2V2/T2 (thats what i tried)

The Attempt at a Solution


i got answers like 4.8, 1.68 by plugging into the equation...but as usual plug and chug never works...can u help please? i think I am missing how to find pressure from 24 m below surface. how do u do that?
 
Physics news on Phys.org
It would be more helpful to a reader here if you showed the calculations you made, rather than simply giving the answers you found that didn't work. You do want to use the "Ideal Gas Law". Did you use absolute temperatures in your calculation (Kelvins, rather than degrees Celsius)? Did you remember that the pressure at 24 m. down is the hydrostatic pressure of 24 meters of water plus the one atmosphere of pressure from the air above the water's surface?

i think I am missing how to find pressure from 24 m below surface. how do u do that?

Have you had the topic on hydrostatic pressure? The pressure from the water will be

P = (density of water) x (g) x (depth of water).
 
Last edited:
no we haven't covered that so wat pressure wud i used for when its just about to break the surface of the water since i don't know exactly how deep it is? wud that just be 1 atm?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top