Calculating Thermodynamic Values for Different Processes

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SUMMARY

This discussion focuses on calculating thermodynamic values such as q, w, ∆U, ∆H, and ∆S for processes depicted in two figures. The process from A to B in figure 1 is identified as isothermal, allowing for straightforward calculations. For A to B in figure 2, the specific process type is not necessary; instead, the work can be calculated by integrating the area under the curve, which consists of a right-angled triangle and a rectangle. The total work calculated for this segment is 1400 J, derived from the areas of the triangle and rectangle.

PREREQUISITES
  • Understanding of thermodynamic processes, specifically isothermal processes.
  • Knowledge of calculating work in thermodynamics through integration.
  • Familiarity with pressure-volume (pV) diagrams.
  • Basic proficiency in using mathematical formulas for area calculations.
NEXT STEPS
  • Study the principles of thermodynamic cycles and their applications.
  • Learn about different types of thermodynamic processes, including isothermal, adiabatic, and isochoric.
  • Explore advanced integration techniques for calculating work in non-linear processes.
  • Investigate the use of software tools for visualizing and calculating thermodynamic properties.
USEFUL FOR

This discussion is beneficial for students and professionals in thermodynamics, mechanical engineers, and anyone involved in energy systems analysis or related fields.

atsum
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The question is to calculate: q, w, ∆U, ∆H, ∆S for each step(A to B, B to C, C to A)

I know how to calculate the values on figure 1, but, how to calculate A to B on figure 2?

For A to B on figure 1, it is isothermal process, therefore, I can easy to find out the answer, but I don't know what is the process for A to B on figure 2.

Can anyone tell me what the condition difference (A to B) between figure 1 and 2?
 

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atsum said:
For A to B on figure 1, it is isothermal process, therefore, I can easy to find out the answer, but I don't know what is the process for A to B on figure 2.

Can anyone tell me what the condition difference (A to B) between figure 1 and 2?

Hello.

You don't need to know what kind of process is between A and B on picture 2. You simply calculate work by integrating, or simpler, by calculating surface under the AB line. It is easy to calculate, because you have one right angled triangle and one rectangle. (i will do approximation: 1atm=10^5 Pa, a 1L=1dm^3=10^-3 m^3)

Surface of triangle is:

S(t)=\frac{pV}{2}=\frac{5*10^{5}Pa*4*10^{-3}m^{3}}{2}=1000J

Surface of rectangle is:

S(r)=pV=10^{5}Pa*4*10^{-3}m=400J

So, total work is W=S(t)+S(r)=1400J

And now you can calculate everything else.
 

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