Calculating Time Dilation for a Spacecraft Traveling to Proxima Centauri

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SUMMARY

The discussion centers on calculating the velocity required for a spacecraft to reach Proxima Centauri, located 4.3 light-years away, within 3.7 years as experienced by travelers on the spacecraft. The relevant equations include time dilation formulas, specifically Δt = x/(c√(1-v²/c²)) and Δt₀ = 3.7 years. The final results indicate that the spacecraft must travel at approximately 0.759c, resulting in an Earth observer time of 5.68 years. The calculations confirm the accuracy of the derived values with the assistance of forum participants.

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  • Understanding of special relativity concepts, particularly time dilation.
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  • Knowledge of the speed of light (c = 3.0e8 m/s) and its significance in calculations.
  • Ability to manipulate algebraic equations to solve for unknown variables.
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  • Learn about relativistic velocity addition and its application in space travel scenarios.
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grouper
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Homework Statement



The nearest star to Earth is Proxima Centauri, 4.3 light-years away. At what constant velocity must a spacecraft travel from Earth if it is to reach the star in 3.7 years, as measured by travelers on the spacecraft ? How long does the trip take according to Earth observers?

Homework Equations



Earth observer: Δt=x/(c*√(1-v2/c2))=Δto/√(1-v2/c2) where Δto=time observed by person on spacecraft

Δto=3.7 yr=1.164e8 s

x=4.3 ly=4.068e16 m

c=3.0e8 m/s

The Attempt at a Solution



I tried using the two versions of the equation above with the known quantities plugged in such that (1.164e8/√(1-v2/c2)=4.068e16/(c*√(v2/c2)), but this is a false statement, so there must be something wrong with my equations or the way I am using them because that method does not yield an answer. Any help is appreciated, thanks.
 
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grouper said:
Earth observer: Δt=x/(c*√(1-v2/c2))=Δto/√(1-v2/c2) where Δto=time observed by person on spacecraft
I don't quite understand the first part of that equation. Try:
v = Δx/Δt = Δx/(γΔt0)
 
Thanks for the equation corrections! How do I figure out v without knowing Δt though? (or vice versa?)
 
grouper said:
Thanks for the equation corrections! How do I figure out v without knowing Δt though? (or vice versa?)
You know Δt0. Express γ as a function of v. Then you can solve that equation for v, the only unknown.
 
Ok, working that out I got v=0.759c and Δt according to the Earth observers is 5.68 years, both of which are correct. Thanks for the help.
 

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