- #1
tina_singh
- 14
- 0
can some one please help me calculate the time period of the signal cos(pi/8 n*n).
tina_singh said:actually what really confuses me is the term n square..i hav solved similar questions where cos was a function of n(t in continuous time).
please help me with this question..
i will be really greatful
tina_singh said:actually what really confuses me is the term n square..i hav solved similar questions where cos was a function of n(t in continuous time).
please help me with this question..
i will be really greatful
To calculate the time period of cos(pi/8 n*n), you can use the formula T = 2π/ω, where ω is the angular frequency. In this case, ω = pi/4. Therefore, the time period would be T = 2π/(pi/4) = 8 seconds.
The value of pi/8 represents the angular frequency, which is the rate at which the angle of the cosine function is changing. It determines the number of cycles that occur per unit of time.
No, the formula T = 2π/ω is specific to cosine functions. For other trigonometric functions, different formulas may be used to calculate the time period.
The value of n does not have an effect on the time period of cos(pi/8 n*n). It only affects the amplitude of the cosine function.
No, the time period cannot be negative as it represents a measurement of time. However, the cosine function itself can take on negative values depending on the input value of n.