Calculating Time to Catch Up Using Acceleration and Velocity Graphs

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To determine how long it will take for a stopped car to catch up to another car moving at 11 m/s while accelerating at 4 m/s² to a maximum speed of 15 m/s, it's essential to analyze the distance each car travels over time. The key is to calculate the time it takes for the stopped car to reach its maximum speed and the distance covered during that time. By comparing the distances traveled by both cars using a velocity-time graph, the problem can be simplified, eliminating the need to deal with the squared time variable. Drawing the graphs helps visualize the situation and leads to a clearer understanding of the equations involved. Ultimately, this approach will yield the time required for the stopped car to catch up.
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ok, the question is like this, you are in a car stopped at a red light. the light goes green adn a car passes you by going 11.om/s E. if you accelerate at 4.0m/s^2 to a maximum speed of 15m/s. How long will it take for you to catch up.
so i know the distance between them is the same.
i tried to use V*T=1/2*A*T^2 but since the t is squared i don' know what to do with it. can anyone help ?thx
 
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help please ... :frown: :frown: :frown:
 
fannyzhou said:
ok, the question is like this, you are in a car stopped at a red light. the light goes green adn a car passes you by going 11.om/s E. if you accelerate at 4.0m/s^2 to a maximum speed of 15m/s. How long will it take for you to catch up.
so i know the distance between them is the same.
i tried to use V*T=1/2*A*T^2 but since the t is squared i don' know what to do with it. can anyone help ?thx

Ask yourself this: How long will it take for the stopped car to accelerate to 15 m/s, and how far apart are the cars at that point?
 
So.. As you said, since distance is the same, well, you can simply draw out a velocity time graph of both graphs on both diagrams and try working them out right? Its always wiser spending some time drawing the graphs.. Basically, after drawing the graph and working out the equations, you should not be getting a t^2 anymore.
 
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