Calculating Time to Catch Up Using Acceleration and Velocity Graphs

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Homework Help Overview

The problem involves two cars: one that is stationary at a red light and another that passes by at a constant speed. The stationary car accelerates to a maximum speed, and the question is about determining the time it takes for the stationary car to catch up to the moving car. The subject area includes kinematics and motion analysis.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between distance and time for both cars, with one suggesting the use of a velocity-time graph to visualize the problem. Questions arise regarding the implications of using equations that involve time squared.

Discussion Status

Some participants have offered guidance on visualizing the problem through graphing, while others are exploring the implications of the equations involved. There is an ongoing exploration of how to relate the distances traveled by both cars during the acceleration phase.

Contextual Notes

There is mention of a maximum speed for the accelerating car and a constant speed for the other car, which may influence the calculations. The original poster expresses uncertainty about handling the time variable in the equations.

fannyzhou
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ok, the question is like this, you are in a car stopped at a red light. the light goes green adn a car passes you by going 11.om/s E. if you accelerate at 4.0m/s^2 to a maximum speed of 15m/s. How long will it take for you to catch up.
so i know the distance between them is the same.
i tried to use V*T=1/2*A*T^2 but since the t is squared i don' know what to do with it. can anyone help ?thx
 
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help please ... :frown: :frown: :frown:
 
fannyzhou said:
ok, the question is like this, you are in a car stopped at a red light. the light goes green adn a car passes you by going 11.om/s E. if you accelerate at 4.0m/s^2 to a maximum speed of 15m/s. How long will it take for you to catch up.
so i know the distance between them is the same.
i tried to use V*T=1/2*A*T^2 but since the t is squared i don' know what to do with it. can anyone help ?thx

Ask yourself this: How long will it take for the stopped car to accelerate to 15 m/s, and how far apart are the cars at that point?
 
So.. As you said, since distance is the same, well, you can simply draw out a velocity time graph of both graphs on both diagrams and try working them out right? Its always wiser spending some time drawing the graphs.. Basically, after drawing the graph and working out the equations, you should not be getting a t^2 anymore.
 
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