Calculating Torque and Work: Flywheel Mass, Radius, and Time Interval

  • Thread starter Thread starter Jtappan
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
To calculate the torque required to accelerate a flywheel of mass 181 kg and radius 0.63 m to 118 rpm in 29.4 seconds, one must first convert the rpm to angular velocity and determine angular acceleration using the formula Vf = Vi + at. The moment of inertia is calculated using I = mr^2, and torque is found using the relationship T = I * alpha. For the work done during this time interval, the change in kinetic energy should be considered, specifically using the formula for rotational kinetic energy, as the initial kinetic energy is zero. Understanding these principles will lead to the correct calculations for both torque and work.
Jtappan
Messages
95
Reaction score
0

Homework Statement



A flywheel of mass 181 kg has an effective radius of 0.63 m (assume the mass is concentrated along a circumference located at the effective radius of the flywheel).

(a) What torque is required to bring this wheel from rest to a speed of 118 rpm in a time interval of 29.4 s?
_____ N·m

(b) How much work is done during the 29.4 s?
______ kJ


Homework Equations



?

The Attempt at a Solution



How is this problem done when time is involved?? I am confused.

I have done I = mr^2 and that's it.
 
Physics news on Phys.org
they give you 118 rpm. You have to convert that to angular velocity using factor label.

You have time and final angular velocity, so you can find angular acc. using Vf = Vi + at where Vf=final angular vel, Vi = initial angular vel (which is 0 in this case), a=angular acc, and t=time.

then just use your I = mr^2, but remember that T=Ia (torque = I * alpha) and remember that torque=F*d.

Good luck!
 
Bump...I am working on a similar problem and having trouble with part b. I have found the torque and I thought to find work I could use w=td where t is torque and d is rotational distance. What am I missing?
 
Work is the change in kinetic energy. KEf - KEi, but since its at rest in the beginning, its KEf - 0, which is just w=KEf. Remember to consider rotational kinetic energy, because it is rotating. Good luck to you both!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top