Calculating Torque needed to raise an object

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To determine if a motor can rotate a robotic arm, the torque required must be calculated based on the arm's dimensions and material properties. The arm, modeled as a cylinder with a cross-sectional area of 12 cm² and a volume of 720 cm³, has a density of 1.24 g/cm³, leading to a total weight that contributes to the force needed for lifting. Torque is calculated using the formula Torque = Force * Radius, but the challenge lies in the distributed weight along the arm's length. It's crucial to consider the motor's torque at various speeds, as maximum torque typically occurs when stationary. Ultimately, understanding the motor's torque/speed specifications is essential for ensuring it can lift the arm effectively.
kolleamm
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I'm trying to find out if my motor can rotate a robotic arm upwards from a resting position (we can assume the arm is a cylinder for simplicity).

The cylinder has an outer diameter of 5.6 cm , and an inner diameter of 5.0cm
Therefore its cross sectional area in that case should be

pi(2.8)^2 - pi(2.0)^2 = 12.06cm^2 let's just say 12cm^2

Its 60 cm long so its volume should be 12 * 60 = 720 cm^3

Also the density of the plastic material is 1.24g/cm^3 or 0.00124kg/cm^3

The motor has a torque of 40kg/cm

I know that Torque = Force * Radius, but in this case I'm a little unsure of how to calculate the force required since the object is not applying a force at just one point.

We can assume the object starts at the pivot and extends its 60cm size across the arm.
Any help is appreciated.

Thanks in advance
 
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I was finally able to find the solution. I actually had to build a program to run this calculation. The solution is similar to solving the Fibonacci sequence since it requires the data from the previous iterations to check how much torque you have left.
 
kolleamm said:
check how much torque you have left.
With motors, the torque is dependent on rotational speed so you don't so much have "torque left" but "is it enough". You really need to know the speed that the motor will be running at - or the speed you want the arm to lift the mass. A DC type motor will probably have maximum torque when stationary, which may help. Depending on how near the 'performance edge' you are, you may need to know the torque / speed spec of the motor.
PS Torque is in units of kg cm (a product) and not kg per cm.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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