Calculating Torque of Spring Actioned Piston

  • Thread starter Thread starter cutzzzzz
  • Start date Start date
  • Tags Tags
    Piston Spring
AI Thread Summary
To calculate the torque of a spring-actioned piston when the spring is released, two key equations are necessary. The first is Hook's Law, which relates the force exerted by the spring to its compression. The second equation can be derived from a free body diagram, illustrating how the force from the spring translates into torque on the wheel based on the wheel's angular displacement. Understanding these principles will enable accurate torque calculations. This approach provides a foundational understanding for solving the problem presented.
cutzzzzz
Messages
2
Reaction score
0
hi guys, this is my first post (and i am don't know much physics), i have a problem that I've ilustrated in a drawing that i attach to this post. Ok so it goes something like this ... if the spring is compressed manually , when i release it how do i calculate the torque of the wheel?
this is the link to the drawing :
http://i50.tinypic.com/2rfvn21.jpg
 
Engineering news on Phys.org
can some1 help me with this problem??
 
Two equations will be most useful to you. One will be simple Hook's law for the spring. The other you can derive from a simple free body diagram, to show how force at the spring converts to torque to the wheel as a function of angular displacement of the wheel.
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top