Calculating Torque on an Apple: Fx, Fy, Fz

  • Thread starter Thread starter Weatherwizard
  • Start date Start date
  • Tags Tags
    apple Torque
AI Thread Summary
The discussion focuses on calculating torque for an apple located at coordinates (-3.0, 0, 7.0) m due to various force components. The torque about the origin is calculated using the formula T = r x F, where r is the position vector. For a force Fx = 2.0 N, the torque is determined to be -6 N*m. Participants debate the correct application of torque equations, with some confusion over using the correct axis for calculations. Visualizing the problem through drawing is suggested to clarify the concepts involved.
Weatherwizard
Messages
1
Reaction score
0
What is the magnitude of the torque about the origin of an apple at coordinates (-3.0, 0, 7.0) m due to force F whose only component is Fx = 2.0 N?
What is the y-component of this torque?
What is the magnitude of the torque if the force is Fx = - 2.0 N?
What is the y-component of this torque?
What is the magnitude of the torque if the force is Fz = 2.0 N?
What is the y-component of this torque?

t=Ia or is there another equation?


t=-3*2.0 N= -6 N*m
I did N*m for the other ones but still getting the answer wrong.
 
Physics news on Phys.org
If (-3.0, 0, 7.0) is a point in 3D space (x,y,z) then...

t=-3*2.0

is that T = x * F ?

I believe that should be T = z * F

Draw it.
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Calculation of resulting force from out of axis Torque
Replies
21
Views
3K
Where on a rigid body is a resultant force applied?
Replies
11
Views
1K
Rotating rod of negligible mass attached to two point masses
Replies
19
Views
4K
Blocks falling while attatched to pulley
Replies
6
Views
2K
Effect of different magnetic fields on a magnetic dipole
Replies
25
Views
1K
Wooden sphere rolling on a double metal track
2
Replies
97
Views
5K
What is the formula for calculating torque in a rotating pyramid?
Replies
24
Views
2K
A ladder against a wall problem
Replies
5
Views
2K
How Much Load Can a 300-kg Beam Support Before Exceeding Strut Safety Limits?
Replies
3
Views
1K
How Do You Calculate Torque on a Wrench?
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top