Calculating Torque with Angled Forces: A New Perspective

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Torque can be calculated using the formula Fd, where F is the force and d is the distance from the pivot. When a force is applied at an angle, it can be resolved into horizontal and vertical components. The horizontal component, calculated using F sin(angle), can be used with the perpendicular distance from the pivot to determine torque. The discussion emphasizes that the torque formula involves the cross product of the force vector and the distance vector, incorporating the sine of the angle. This approach provides a valid method for calculating torque with angled forces.
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i was wondering the other way to calculate torque
as it is calculated by Fd, F=force and d= distance from pivot.
my question is... originally, torque is calculated by extending the line of force until it is perpendicular to the pivot. then that distance X force is the value of torque.
i was wondering, if the force is at an angle to the place of contact, could we not just split the force into horizontal and verticle force? and then use the horizontal force (given by F sin (angle)) and measure the distance from pivot from the point of contact which is already perpendicular to the pivot, please give some thoughts...i duno if its right...:rolleyes:
 
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yup, just like many things in physics...torque formula is the dot product between the force vector and the "distance" vector. so yes, you will get a sin or cos of an angle depending where you define your angle. but the idea is the same.

edit: sorry I meant to say cross product, convention is use sin of an angle
 
Last edited:
minijumbuk said:
i was wondering the other way to calculate torque
as it is calculated by Fd, F=force and d= distance from pivot.
my question is... originally, torque is calculated by extending the line of force until it is perpendicular to the pivot. then that distance X force is the value of torque.
i was wondering, if the force is at an angle to the place of contact, could we not just split the force into horizontal and verticle force? and then use the horizontal force (given by F sin (angle)) and measure the distance from pivot from the point of contact which is already perpendicular to the pivot, please give some thoughts...i duno if its right...:rolleyes:

Very good, you are correct.
 
cyrusabdollahi said:
Very good, you are correct.
WOOHOO! XD
lol thanks...that clears it up alot:smile:
 
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