Calculating Total Energy Loss of a Newton's Cradle

AI Thread Summary
To calculate the total energy loss of a Newton's cradle, start by measuring the maximum horizontal displacements and angles of the swings. Use these values to determine the maximum vertical displacement of the ball, which allows for the calculation of maximum gravitational potential energy (GPE) when kinetic energy is zero. The energy loss can be found by comparing the initial GPE with the final state when the system comes to rest, where kinetic energy is zero and GPE is at its minimum. The only energy input occurs when the first ball is lifted, as the system does not gain mechanical energy after release. Understanding these principles will guide the calculation of energy loss effectively.
faunmia
Messages
6
Reaction score
0
How can I measure the total energy loss of a Newton's cradle until it comes to rest. The only variables I am given are the horiztonal displacements for each swing (how far the ball travels out after it rebounds off the other balls) and the angle. I have no idea where to start, I was told I should be able to work out velocity from the displacements and gravity(9.8m/s). The equations I have are
KE = mv²/2
p = mv
I am not asking for anyone to do this for me, but rather a starting point which I can work from
 
Physics news on Phys.org
Calculate the maximum vertical displacement of the ball, from that you can calculate the maximum gravitational potential energy, when it's kinetic energy is zero.

When the system comes to rest, it will have no kinetic energy and it will be at it's minimum gravitational potential energy.

The difference between the two therefore, is the value you calculate for GPE.
 
Adding to lavalamp, the only energy that was added was the work you did on the first ball to give it potential. The system certainly is not gaining any mechanical energy once you release the first ball.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top