Calculating Total Resistance & Tolerance of 2 Wires

AI Thread Summary
The total resistance of two wires, one with 50 Ohms and 5% tolerance and the other with 60 Ohms and 3% tolerance, is 110 Ohms. The total tolerance is calculated by determining the error in the sum of their tolerances, resulting in a total tolerance of 8%. The first wire's resistance range is from 47.5 Ohms to 52.5 Ohms, while the second wire's range is from 58.2 Ohms to 61.8 Ohms. Adding these ranges gives a total range of 105.7 Ohms to 114.3 Ohms. Thus, the total tolerance confirms to be approximately 8.15%.
UrbanXrisis
Messages
1,192
Reaction score
1
If there were 2 wires, and one of the wire has a resistance of 50 Ohms with a tolerance of 5%, while the second wire has a resistance of 60 Ohms with a tolerance of 3%. The total resistance would be 110 Ohms but what about the total tolerance? Would it be 8%?
 
Physics news on Phys.org
The first one is 50+/-2.5, and the second is 60+/-2. The error in the sum is sqrt(2.5^2+2^2)=3 ohms. This equates to 3%.
 


Yes, the total tolerance would be 8%. This can be calculated by finding the range of possible resistance values for each wire and then adding them together. For the first wire, the range would be 47.5 Ohms to 52.5 Ohms (50 Ohms +/- 5%). For the second wire, the range would be 58.2 Ohms to 61.8 Ohms (60 Ohms +/- 3%). When added together, the total range is 105.7 Ohms to 114.3 Ohms. This means that the total tolerance is 8% (8.6 Ohms / 105.7 Ohms = 0.0815 = 8.15%).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top