Calculating Velocity of Sphere on Inclined Plane

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The discussion focuses on calculating the velocity of a sphere as it rolls up a 25-degree incline. The sphere has an initial translational speed of 10 m/s and a mass of 25 kg, with a moment of inertia defined as I=2mr²/5. The user calculated the total kinetic energy, including translational and rotational components, and added potential energy (mgh), resulting in a total of 3015 J. However, confusion arose regarding the final velocity, as the calculated speed of 15.53 m/s seemed incorrect since the sphere should not speed up while ascending the incline. Clarification was sought on the inclusion of potential energy in the calculations.
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Homework Statement


A large sphere rolls wothout slipping across a horizontal surface. The sphere has a constant translational speed of 10m/s,mass of 25 kg, radius of .2m. The moment of inertia of the sphere about its center of mass is I=2mr2/5. The sphere approaches a 25 degree incline of height 3m as shown above and rolls up the incline without slipping. Calculate the spheres velocity just as it leaves the top of the incline.

Homework Equations





The Attempt at a Solution


I found total kinetic energy by adding translational kin enery, rotational kin energy and (mgh)... i got 3015J and then set that number equal to the equation for kin energy (1/2mv2) and found my new v and got 15.53 m/s but that can't be correct bc if its initial vel as it was going toward the ramp was 10 m/s then why would it speed up if its going up a ramp? idk what i did wrong pleaseee help.!
 
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moondawg said:
I found total kinetic energy by adding translational kin enery, rotational kin energy and (mgh)...
Why did you add mgh? Explain exactly what you did.
 
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