Calculating Velocity Using Spring Force and Energy Conservation

AI Thread Summary
The discussion focuses on calculating the velocity of a block subjected to a force of 500 N while considering the spring force and energy conservation principles. The initial conditions state that the block is at rest and the spring is uncompressed at s = 0. Participants note the challenge of dealing with the variable nature of spring force and suggest using the average force or conservation of energy for a more straightforward solution. Emphasis is placed on correctly applying the conservation of total energy equation to avoid confusion with mechanical energy conservation. The conversation highlights the importance of understanding these concepts to solve the problem effectively.
driven4rhythm
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Homework Statement


http://img682.imageshack.us/img682/8177/f141.jpg http://g.imageshack.us/img682/f141.jpg/1/
If the block is subjected to a force of = 500 , determine its velocity when = 0.6 . When = 0, the block is at rest and the spring is uncompressed. The contact surface is smooth. The spring is placed between the wall and the 6-block.

Homework Equations


Unsure

The Attempt at a Solution


I converted F to F along x-axis and it's equal to 400N. I took the integral of F=k*ds from 0 to .6 and got 300N in the negative x direction. I know that as s changes the force does and thus the acceleration is different all the time. I just can't figure out what to do with the spring force.
 
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Recall that Newton's law actually says,

ma = The sum of the forces. Therefore you need to start with

m\frac{d^2x}{dt^2} = 400 - kx
 
driven4rhythm said:

Homework Statement


http://img682.imageshack.us/img682/8177/f141.jpg http://g.imageshack.us/img682/f141.jpg/1/
If the block is subjected to a force of = 500 N[/color], determine its velocity when s[/color] = 0.6 m[/color] . When s[/color] = 0, the block is at rest and the spring is uncompressed. The contact surface is smooth. The spring is placed between the wall and the 6 kg[/color] block.

Homework Equations


Unsure

The Attempt at a Solution


I converted F to F along x-axis and it's equal to 400N. I took the integral of F=k*ds from 0 to .6 and got 300N in the negative x direction. I know that as s changes the force does and thus the acceleration is different all the time. I just can't figure out what to do with the spring force.
See my notes above in red. They are my assumtions, since you left out the units. You are going to get into some difficulty by using your method, because the spring force is a variable force. You can still determine it as an average force ( ks/2), and use Newton's laws and the kinemaric equations to solve for v, but it's easier to use conservation of total energy, if you are familiar with it . Are you?
 
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PhanthomJay said:
See my notes above in red. They are my assumtions, since you left out the units. You are going to get into some difficulty by using your method, because the spring force is a variable force. You can still determine it as an average force ( ks/2), and use Newton's laws and the kinemaric equations to solve for v, but it's easier to use conservation of total energy, if you are familiar with it . Are you?

Sorry I didn't realize when I copied the problem over that the numbers and such were pictures and not text. Yes, I am familiar with conservation of energy.
 
driven4rhythm said:
Sorry I didn't realize when I copied the problem over that the numbers and such were pictures and not text. Yes, I am familiar with conservation of energy.
Good, give it a try using the energy method, it'll save you a lot of heartache, I would think. Just don't confuse the conservation of mechanical energy equation (delta K + delta U = 0) with the conservation of total energy equation (delta K + delta U = work done by non conservative forces). Use the latter.
 
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