Calculating Vertical Velocity of Propagating Waves in a String

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To calculate the vertical velocity of the string at x=2m and t=5s for two propagating waves, the combined wave function g(x,t) is defined as the sum of the individual wave equations y1 and y2. The necessary parameters, such as angular frequency (w) and wave number (k), are derived using the known wavelengths and amplitudes. Differentiating g with respect to time provides the vertical velocity, which is then evaluated at the specified coordinates. The approach taken is confirmed as correct by peers in the discussion. This method effectively utilizes the standard wave equations and relationships for accurate results.
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Homework Statement



Two waves are propagating in a long uniform string of linear mass density μ and tension Fτ.
Their equations are:

y1=A1cos(k1x-w1t)
y2=A2cos(k2x-w2t)

Known: λ1 (wavelength of y1), λ2, A1, A2

what is the vertical velocity of the string at x=2m and t=5s?

Homework Equations



v=sqrt(Fτ/μ)=w/k
k=2π/λ
standard wave equation and solutions

The Attempt at a Solution



just to check I'm on track. what I did was defining:
g(x,t)=y1+y2 and finding all the missing varibles (w,k) using formulas.
I then differentiated g with respect to t and plugged x=2,t=5 in the derivative

is this correct?
 
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susdu said:

Homework Statement



Two waves are propagating in a long uniform string of linear mass density μ and tension Fτ.
Their equations are:

y1=A1cos(k1x-w1t)
y2=A2cos(k2x-w2t)

Known: λ1 (wavelength of y1), λ2, A1, A2

what is the vertical velocity of the string at x=2m and t=5s?

Homework Equations



v=sqrt(Fτ/μ)=w/k
k=2π/λ
standard wave equation and solutions

The Attempt at a Solution



just to check I'm on track. what I did was defining:
g(x,t)=y1+y2 and finding all the missing varibles (w,k) using formulas.
I then differentiated g with respect to t and plugged x=2,t=5 in the derivative

is this correct?

That would be the correct procedure, yes.
 
thanks!
 
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