Calculating Weight on an Incline

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To solve for the actual weight and angle of incline given a perpendicular weight of 390 and a parallel weight of 330, the relationship between these weights and the angle must be established. The perpendicular weight is associated with the sine of the angle, while the parallel weight relates to the cosine. By using the ratio of the two weights, the angle θ can be calculated through the inverse function. This approach allows for determining both the gravitational force and the incline angle effectively. The discussion emphasizes the importance of understanding vector relationships in incline problems.
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Homework Statement


perpendicular weight is given,
Parallel weight is given
Need to find actual weight and angle of incline


Homework Equations





The Attempt at a Solution

 
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Welcome to PF.

Can you be a little more specific?
 
I am given a problem that states the perpendicular weight is 390 and the parallel weight is 330 and it ask to find the weight or force of gravity and the angle of the incline. I know that the perpendicular weight is equal to mgsine theta, and the parallel weight is mgcosin theta.
 
Nick Leeson said:
I am given a problem that states the perpendicular weight is 390 and the parallel weight is 330 and it ask to find the weight or force of gravity and the angle of the incline. I know that the perpendicular weight is equal to mgsine theta, and the parallel weight is mgcosin theta.

Since they are vectors, then won't the ratio of the two be an expression of θ ?

Then just take the inverse to find θ .
 

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