Calculating Work Done: Understanding the Relationship between Force and Distance

[synkk]

So I'm trying to get ahead of the class for next year and I've started reading this physics book, now I've come along to work and I'm slightly confused on what's happening.

Homework Statement

A force of 10 Newtons to the north-east acts on an object as it moves 25 metres to the south-east. What is the work done by the force?

Homework Equations

W = F*d

The Attempt at a Solution

I've tryed to use trigonometry to solve this, but i don't think i done it correct as the answer is 0J

cos = A/h

a = 25

25/cos45 = h

h * 10 = W

I get around 353J which is completely wrong.

If anyone could help me out, it'd be great.

 

[omega_minus]

synkk,

The problem does sound misleading with the term "north-easterly direction" as though it is not displaced exactly to the north east. However the 45 degree angle makes me think it is exactly to the north east (i.e. 45 degrees away from the north). Kudos on trying to get ahead!

 

[synkk]

Thank you i managed to solve a few more problems, my bad on not reading it properly :).

I'm going to update the thread with a new question which I am frankly baffled at.