Calculation trafo chiral multiplet

  • Thread starter Thread starter hendriko373
  • Start date Start date
  • Tags Tags
    Calculation Chiral
hendriko373
Messages
14
Reaction score
0
Hello,

I'm trying to deduce the suspersymmetry transformation of the chiral multiplet out of the superfield formalism. In doing this I got stuck with this:

\theta^{\alpha}\sigma^{\mu}_{\alpha\dot{\alpha}}\overline{\sigma}^{\dot{\alpha}\beta}_{\nu}\theta_\beta(\partial_\mu\psi_\gamma\sigma^{\nu}_{\gamma\dot{\gamma}}\overline{\xi}^{\dot{\gamma}})

Here I wrote all the indices explicitly, with the undotted and dotted respectively left and right handed 2D Weyl indices (theta's anti commuting).

What bothers me is the part in front of the paragraphs, I would like to get something like this:

\theta^{\alpha}\epsilon_{\alpha\beta}\theta^\beta(\partial_\mu\psi_\gamma\sigma^{\mu}_{\gamma\dot{\gamma}}\overline{\xi}^{\dot{\gamma}})

Notice that there is the contraction now in the paragraph on space time indices. I think it's not that difficult, one has to use the clifford algebra commutation relation I guess, but I don't see it coming out. Maybe tracing over it would also work. Any help would be appreciated much.

greetz

hendrik
 
Physics news on Phys.org
Ok I solved it. For those interested, use the defining equation for the clifford algebra and the fact that the antisymmetric part in spacetime indices is symmetric in its weyl indices, such that this term is zero when combined with the antisymmetry of the theta's. This gives a kronecker delta for both weyl and space time indices, giving the desired result.

cheers
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top