:-$ Calculus Based Physics: Newton's Laws Problem

Click For Summary

Homework Help Overview

The discussion revolves around a calculus-based physics problem involving Newton's laws, specifically focusing on the motion of a robot in a nuclear power plant under a given force function. The original poster seeks to determine the instantaneous speed of the robot at the end of a specified time interval, starting from rest.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration of an acceleration function to find velocity, with some questioning the complexity of variables involved. There are inquiries about how to handle constants and the integration process itself.

Discussion Status

The conversation reflects a mix of attempts to clarify the integration process and the challenges faced by the original poster, particularly regarding the use of a calculator for integration. Some participants provide guidance on integrating with respect to the variable t and emphasize the importance of understanding the underlying concepts rather than relying solely on calculators.

Contextual Notes

There is mention of the original poster's educational background, indicating a lack of prior calculus knowledge despite being enrolled in a calculus-based physics class. This context raises questions about the appropriateness of the problem given their current level of understanding.

johnsonandrew
Messages
88
Reaction score
0
Homework Statement
A robot working in a nuclear power plant moves along a straight track. If it experiences a force

F(t) = -Fi [ 1 + (4.0t - 2.0T)/T ]

where T is a constant with the units of time, what is the instantaneous speed of the robot at the very end of the interval 0 [tex]\leq[/tex] t [tex]\leq[/tex] T. It was at rest at t= 0

Relevant equations

ma = -Fi [ 1 + (4.0t - 2.0T)/T ]

[tex]\int[/tex] a(t) = v(t)


How do I integrate that?? it will be a = [ -Fi [ 1 + (4.0t - 2.0T)/T ] ] / m
but how do I integrate with so many variables... do I plug in t for T? No mass given...
 
Physics news on Phys.org
I'm sorry? "so many variables"? There is only one variable: t. Integrate with respect to t.
 
Your integral should be [tex]v=\int a dt +C[/tex] for some constant. Now, you are correct in saying that a=[ -Fi [ 1 + (4.0t - 2.0T)/T ] ] / m. You are told in your question that T is a constant, so you should be able to integrate this expression, using the limits given.
 
Well I tried putting [tex]\int[/tex] [ -Fi [ 1 + (4.0t - 2.0T)/T ] ] / m , t into my TI-89 and it didn't integrate. It simply returned " -[tex]\int[/tex] [ Fi [ 1 + (4.0t - 2.0T)/Tm ] dt
I figured it couldn't be integrated since the calculator won't do it, and that I must have set it up wrong. I guess not. Is there any way I can get this to work on my calculator (on the TI-89)? I have not yet learned integration in my Calculus class, so for now those of us unable to do integration are expected to simply punch it in our calculators.
 
Last edited:
You should learn that there are some things that calculators cannot do; especially those things that one needs a brain for. I imagine there is a way to do it, but I don't own a graphic calculator so couldn't tell you. You would need to tell the calculator that T, Fi and m are constants, and that you are integrating wrt t.

However, if your teacher actually told you to use a calculator, and gave you this problem knowing full well you hadn't covered calculus, then I suggest you simply write the integral. Classes like this should not be telling students to use calculators instead of performing calculations by oneself.
 
No, you're right, and I understand that. I'd much rather know how to do the problem longhand. Unfortunately my high school is not big on physics, so the only AP course offered this year is calculus-based. The prerequisite for the class is only pre-calculus, not calculus, surprisingly. It only requires simultaneous enrollment in calculus. I wonder why that is, when they are giving us problems like this at the beginning of the year. We have only just finished covering derivatives, and that’s all. Oh well, thanks for your help, I'll let my teacher know and see what she says. :-s
 

Similar threads

  • · Replies 42 ·
2
Replies
42
Views
6K
  • · Replies 5 ·
Replies
5
Views
928
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
1K
Replies
3
Views
4K
Replies
13
Views
3K
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K