Calculus - Equillibrium of band with mass

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Homework Help Overview

The problem involves the motion of a mass attached to an elastic band, described by the equation of motion s = 2 cos t + 3 sin t. The discussion focuses on determining the equilibrium position and related aspects of the motion, such as velocity and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conditions under which the mass passes through the equilibrium position, with one suggesting that it may relate to when the velocity function equals zero. Others explore the implications of forces acting on the mass at equilibrium and the relationship between maximum and minimum values of the motion.

Discussion Status

The discussion is active, with participants offering various perspectives on how to approach finding the equilibrium position. There is an exploration of different methods, including the use of derivatives and the properties of sine and cosine functions, but no consensus has been reached yet.

Contextual Notes

Participants are navigating assumptions about the motion and the definitions of equilibrium in the context of the problem. The original poster expresses uncertainty about their approach, particularly regarding the timing of passing through the equilibrium position.

JonGarces
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Homework Statement


An elastic band is hung on a hook and a mass is hung on the lower end of the band. When the mass is pulled downward and then released, it vibrates vertically. The equation of motion is s = 2 cos t + 3 sin t, t≥0, where s is measured in cm and t in seconds. (Take the positive direction to be downward.)

a) Find the Velocity and acceleration at time t. *Easy and done*
b) Graph velocity and acceleration functions. *Easy and done*
c) When does the mass pass through the equilibrium position for the first time?
d) How far from its equilibrium position does the mass travel?
e) When is the speed the greatest?

Homework Equations


s(t) = 2 cos t+3 sin t
v(t)= - 2 sin t+3 cos t
a(t)= - 2 cos t - 3 sin t

The Attempt at a Solution



I'm stumped at c. What I'm thinking is when the velocity function equals 0, but when i think more into it it starts to not make sense. Any advice is appreciated.
 
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Are there any forces acting on the mass in the instant it's at its equilibrium position? What does that tell us about the acceleration at that instant?
 
Spring motion will go equal distances on either side of the "equilibrium" point so one way to find the equilibrium is to find the maximum and minimum value and take half way between. Since this s is given by sine and cosine, another way to find the equilibrium is to write it as a single sine function.
 
Alright thank you, basically I'm looking for the point of inflection. Aka where the 2nd derivative equals zero.
 

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