Apparently I'm doing something wrong. I'm kind of lost as to what because I looked over my work several times.
sin^2 x = ( 1 - cos 2x )/2
cos^2 x = ( 1 - sin 2x )/2
integral sin(x) dx = -cos(x)
integral cos(x) dx = sin(x)
The Attempt at a Solution
Wolfram Alpha says the correct solution is 1/64 (24 x+8 sin(4 x)+sin(8 x))+constant
Thanks for any help you can provide!
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