Calculus with inverse trig functions

famallama
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Homework Statement


Evaluate the integral of (1/Sqrt(5x-x^2))


Homework Equations


[d/dx]{arcsin(x)}=(du/dx)/sqrt(1-x^2)


The Attempt at a Solution


arcsine(2x-5)/5


I did end up getting the right answer, but have no idea how I got there.
 
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So we have

\int \frac{1}{\sqrt{5x-x^2}}

try completing the square for 5x-x2 (i.e. put it into the form a[x+h]2+k)
 
I have tried that, but the 5 is what is throwing me off.
 
famallama said:
I have tried that, but the 5 is what is throwing me off.

5x-x2 = -(x2-5x) = -(x+5/2)2+k. Can you find 'k'?
 
thank you very much
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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