1. The problem statement, all variables and given/known data calorimeter mass = 60 g calorimeter and water mass = 290 g temperature of cal. and water = 30 C temp of steam = 90 C mass of cal, water, and steam = 300 g specific heat of cal = .1 cal/g C final temp of cal, water, and steam = 80 C Find the Lv for this steam. 2. Relevant equations (a space between the variables means multiply) m Lv + m c (change in temp) = m c (change in temp) + m c (change in temp) m Lv is steam, the 1st m c T is steam water, the 2nd is water, and the 3rd is the cal, and i actually have no idea what Lv is... 3. The attempt at a solution 10 x Lv + 10 2.01 -10 = 230 4.19 50 + 60 (.1 x 4.19) 50 i came up with 4964.3, but i dont know if it is right, or if i even did it right.