calorimeter mass = 60 g
calorimeter and water mass = 290 g
temperature of cal. and water = 30 C
temp of steam = 90 C
mass of cal, water, and steam = 300 g
specific heat of cal = .1 cal/g C
final temp of cal, water, and steam = 80 C
Find the Lv for this steam.
(a space between the variables means multiply)
m Lv + m c (change in temp) = m c (change in temp) + m c (change in temp)
m Lv is steam, the 1st m c T is steam water, the 2nd is water, and the 3rd is the cal, and i actually have no idea what Lv is...
The Attempt at a Solution
10 x Lv + 10 2.01 -10 = 230 4.19 50 + 60 (.1 x 4.19) 50
i came up with 4964.3, but i dont know if it is right, or if i even did it right.