Camshaft design from wanted torque

  • Thread starter Thread starter gogogsr
  • Start date Start date
  • Tags Tags
    Design Torque
AI Thread Summary
The discussion revolves around designing a cam for a test jig that simulates a train caliper, requiring specific torque at various degrees of rotation. The user is struggling with creating a radial cam from torque values, noting discrepancies in pressure angle calculations that lead to insufficient torque. A suggestion is made to interpret the torque curve as a displacement diagram for the spring attachment point on the cam follower, while highlighting challenges due to discontinuities in the curve. The need for a sketch of the entire system is emphasized to clarify the design and facilitate further assistance. Overall, the conversation focuses on the complexities of cam design in relation to torque requirements.
gogogsr
Messages
9
Reaction score
0
Hey guys, I'm making a test jig that needs to simulate a train caliper. The test jig consist of an arm that rotates 90 degrees. The jig must give a certain amount of torque at every degrees (see graph below). I was thinking on making a cam with an eccentric roller follower and die spring. The thing is I'm having a hard time to design the cam from the torque values. I've been able to simulate a sliding cam easily but when it comes to a radial cam its a lot more tricky, everything works with my calculations, except the pressure angle which is almost always 10 time smaller, so the torque is way less then wanted. I'm not sure if i need to determine the envelop of the cam depending on the previous point calculated or not.Any help would be appreciated.

Thanks guys

torquegraph.jpg
 
Engineering news on Phys.org
If I have read your message correctly, we make interpret the torque curve you gave as the required displacement for the spring attachment point on the cam follower since that will generate the strain in the spring to create the force. Thus, with a different scale, this is a cam displacement diagram, for some point on the cam follower.

This presents problems right away in looking at the curve because it has a discontinuous derivative a several locations. This is difficult to do with a cam; cams are inherently smooth devices.

May I suggest that you include a sketch of your entire system if you want further help? It is not very clear what you are trying to accomplish here.
 
i will try to post a sketch tomorrow, thanks for the reply
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
Thread 'How can I find the cleanout for my building drain?'
I am a long distance truck driver, but I recently completed a plumbing program with Stratford Career Institute. In the chapter of my textbook Repairing DWV Systems, the author says that if there is a clog in the building drain, one can clear out the clog by using a snake augur or maybe some other type of tool into the cleanout for the building drain. The author said that the cleanout for the building drain is usually near the stack. I live in a duplex townhouse. Just out of curiosity, I...

Similar threads

Replies
9
Views
4K
Replies
3
Views
2K
Replies
9
Views
1K
Replies
2
Views
1K
Replies
5
Views
5K
Replies
19
Views
11K
Replies
9
Views
4K
Back
Top