Can a Car Move Up a Hill with Only 30N of Frictional Force?

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A car on a hill is analyzed with a 100N force applied to the axle and a frictional force of 30N. The torque generated by the axle is calculated to be 10Nm, while the frictional torque is 6Nm, resulting in a net torque of 4Nm available for acceleration. The discussion assumes that the forces are balanced, indicating that the car can move up the hill despite the low frictional force. The scenario suggests that the car may be a toy due to the minimal frictional force required for movement. Overall, the car is capable of climbing the hill under the given conditions.
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Homework Statement


A car is on a hill. A force of 100n is applied to the axel by the motor in order to move the wheel.The frictional force btwn the wheel and the street is 30N. will the car move up the hill?
also the radius of the axel is 10cm and the radius of the wheel is 20cm. the angle in the picture is 135 degrees

Homework Equations





The Attempt at a Solution

i drew a force diagram. see pic . i came up with 10MN being applied and 6MN for the torque of friction. so yes it does
 

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Yes you are right. The car is able to climb!

Assuming the forces on the incline are balanced (ie net forces are zero. Since the mass is not given, we can't verify that. But since it is not given, it means that the forces are balanced and the car is not moving backward with the wheels spinning forward)

So equilibrium of the forces are assumed.

So it is a matter of how much torque is generated by the axle.

axle torque = 100 * 0.1 = 10Nm
Frictional torque = 30 * 0.2 = 6 NM

So obviously we have 10 - 6 = 4 Nm of torque that is available for acceleration!
 
But it is ridiculous that the frictional force that propels the car up hill is only 30N !
Looks like this is a toy car - cozy coupe :-)
 
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