Can a Counterexample Disprove This Prime Number Statement?

mr_coffee
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Hello everyone. I'm wondering if I'm allowed to use a counter example to disprove this. I'm not sure if I'm understanding the statement correctly though. THe directions are:
Determine whether the statement is true or false. Justify your answer with a rpoof or a counterexample.

Here is the question:
FOr all integers n, if n is prime then (-1)^n = -1.

If it says for ALL integers n, doesn't this mean negatives as well? If it said for All positive integers than wouldn't it be true? But if i let n = -1, i would get (-1)^(-1) = 1, not -1. But if they said, for all integers n, if n is prime..does this mean they are saying n > 1?
 
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The assertion can be rewritten as: For all prime integers n, (-1)^n = -1

Typically, the term 'primes' is restricted to the positive integers.

Yes, you can use a counter example to disprove it.
 
I think it means if n is prime. The integer n seems to be superfluous information.
 
Would this be enough to prove it?
For all integers n, if n is prime then (-1)^n = -1.

False. By definition of a prime number, 2 is an integer and also prime. (-1)^(2) = 1 != -1.

Thanks guys, i actually forgot 2 was a prime number until you said it could be proved with a counter example :blushing:
 
mr_coffee said:
Here is the question:
FOr all integers n, if n is prime then (-1)^n = -1.

If it says for ALL integers n, doesn't this mean negatives as well? If it said for All positive integers than wouldn't it be true? But if i let n = -1, i would get (-1)^(-1) = 1, not -1. But if they said, for all integers n, if n is prime..does this mean they are saying n > 1?

Just to clarify (-1)^(-1) IS equal to -1 not 1.
 
hah whooops u are right, thanks
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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