Can Any Refrigerator Surpass a Carnot Refrigerator in Efficiency?

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Homework Statement



Show that no refrigerator operating between two reservoirs at a given temperature can have higher co-efficient of performance than a Carnot refrigerator operating between the same two reservoirs.

Homework Equations


The Attempt at a Solution



Please check if I am correct


A perfect refrigerator is one in which no work is required to take heat from the low temperature region to the high temp. region.
This is not possible according to the second law of Thermodynamics
The coefficient of performance of a refrigerator
COP = QL / W
where W = work done
from the first law of thermodynamics we can write
COPideal = QL / ( QH - QL )
= TL / ( TH - TL )
= ( TL / TH) / [ 1 - ( TL / TH) ]
= ( TL / TH) / eideal
= analagous to an ideal Carnot refrigerator
 
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I'd prove this by contradiction.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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