Can anyone help my start this problem?

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To calculate centripetal acceleration for a point on a grinding wheel, the formula Ac = v^2 / r is used, where v is tangential velocity and r is the radius. The wheel's angular speed of 12.0 rad/s needs to be converted to tangential velocity using the relationship v = ωr. For a point 0.100 m from the center, the correct formula for centripetal acceleration is Ac = ω^2r, which gives a result of 14.4 m/s² when calculated correctly. The initial miscalculation of 1440 was due to using angular velocity directly instead of converting it to tangential velocity. Understanding the distinction between angular and tangential quantities is crucial for solving such problems accurately.
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A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?
 
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First state the formula for centripetal acceleration. Then look for those quantities in the problem statement.

Give it a try. If you get stuck then post what you have done and where you got stuck. But you must show an attempt at the problem in order to receive help here.
 
Ac= v^2 / r

12^2 / .100 which I got 1440. and the answer is 14.4
 
It is true that centripetal acceleration = v^2/r, where v is the tangential velocity.

However, the 12 you are using is angular velocity. You may convert this \omega = \frac{v}{r} or use the alternative formula: a_c = \omega^2r
 
:blushing: ooh...thanks for the help :smile:
 

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