Can anyone help my start this problem?

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SUMMARY

The discussion focuses on calculating the centripetal acceleration of a point on a grinding wheel with a radius of 0.150 m and an angular speed of 12.0 rad/s. The correct formula for centripetal acceleration is stated as a_c = ω²r, where ω is the angular velocity and r is the radius from the center. Participants clarify that the initial attempt using linear velocity was incorrect, leading to confusion in the calculation. The final correct centripetal acceleration for a point 0.100 m from the center is determined to be 14.4 m/s².

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A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?
 
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First state the formula for centripetal acceleration. Then look for those quantities in the problem statement.

Give it a try. If you get stuck then post what you have done and where you got stuck. But you must show an attempt at the problem in order to receive help here.
 
Ac= v^2 / r

12^2 / .100 which I got 1440. and the answer is 14.4
 
It is true that centripetal acceleration = v^2/r, where v is the tangential velocity.

However, the 12 you are using is angular velocity. You may convert this \omega = \frac{v}{r} or use the alternative formula: a_c = \omega^2r
 
:blushing: ooh...thanks for the help :smile:
 

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