Can anyone help my start this problem?

  • Thread starter Thread starter physics_ash82
  • Start date Start date
AI Thread Summary
To calculate centripetal acceleration for a point on a grinding wheel, the formula Ac = v^2 / r is used, where v is tangential velocity and r is the radius. The wheel's angular speed of 12.0 rad/s needs to be converted to tangential velocity using the relationship v = ωr. For a point 0.100 m from the center, the correct formula for centripetal acceleration is Ac = ω^2r, which gives a result of 14.4 m/s² when calculated correctly. The initial miscalculation of 1440 was due to using angular velocity directly instead of converting it to tangential velocity. Understanding the distinction between angular and tangential quantities is crucial for solving such problems accurately.
physics_ash82
Messages
18
Reaction score
0
A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?
 
Physics news on Phys.org
First state the formula for centripetal acceleration. Then look for those quantities in the problem statement.

Give it a try. If you get stuck then post what you have done and where you got stuck. But you must show an attempt at the problem in order to receive help here.
 
Ac= v^2 / r

12^2 / .100 which I got 1440. and the answer is 14.4
 
It is true that centripetal acceleration = v^2/r, where v is the tangential velocity.

However, the 12 you are using is angular velocity. You may convert this \omega = \frac{v}{r} or use the alternative formula: a_c = \omega^2r
 
:blushing: ooh...thanks for the help :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

What is the Linear Distance and Angular Velocity of a Rotating Potter's Wheel?
Replies
7
Views
2K
Angular velocity and angular acceleration of a turbine
Replies
17
Views
3K
Tangential acceleration and centripetal acceleration
Replies
5
Views
2K
Moment of inertia of a wheel: linear to angular motion
Replies
6
Views
2K
Brake mechanism in a car and pressurised oil
Replies
4
Views
2K
Finding centripetal acceleration of a CD
Replies
3
Views
6K
What's the source of increase in rotational energy of carousel?
Replies
9
Views
2K
Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
What is the angular speed of the rollers after 1.14 s?
Replies
2
Views
1K
Angular Momentum Problem: Mouse walking on a rotating turntable
Replies
5
Views
1K

Hot Threads

Recent Insights

Back
Top