I have two problems that I need help with.(adsbygoogle = window.adsbygoogle || []).push({});

1) A baseball leaves a bat with a velocity of 35 m/s at an angle of 32 degrees. (A) What is the highest point in its path? (B) When will it strike a billboard in center field 8 m above the playing field.

Here's what I have for step (A):

Vf² - Vi²/2a= (0m/s)² - (35m/s)² / 19.6m/s²= -62.5 m

For step (B), would it just be: t=d/v= 8m/35m/s= .229 s ?

2) A rifle bullet is fired in a horizontal direction and strikes the bull's-eye 50m down range. The center of the bull's-eye is 100mm below the rifle's line of sight. What was the muzzle velocity of the bullet?

I don't even know where to begin for this problem.

If anyone can guide me in the right direction for these two problems it would be appreciated. Thank you!

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# Can Anyone Help?

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