I believe I know what you're trying to get at; you're trying to understand what a
field operator really is and on what sort of Hilbert space (the bras and kets) they act. I believe this is best understood by thinking in analogy with elementary quantum mechanics, but I must make a few clarifications before I proceed.
Ray said:
...there is no doubt even at the beginning of the analysis ... that the reader will obtain a wavefunction from which position, momentum and energy can be obtained as eignefunctions.
In elementary quantum mechanics, eigenstates of the position operator are states of
definite position. Such states, in the position representation, are dirac delta functions located at positions. Likewise, eigenstates of the momentum operator are states of
definite momentum, and such states are sinusoidal in the position representation.
Interpretation of such operators in elementary quantum mechanics carry over into the language of quantum field theory quite directly. Classical fields, such as the electromagnetic field, are viewed as the continuum limit of a large collection of (harmonic) oscillators located at every point in spacetime. All oscillators are dynamical and their displacement is interpreted as nonvanishing field values. In other words, if an oscillator at spacetime point (\mathbf{x},\,t) is displaced from its equilibrium value, one interprets this as a nonvanishing field value at (\mathbf{x},\,t).
When moving to the quantum world, the displacement of each oscillator becomes uncertain in spirit of Heisenberg's principle. Furthermore, we may now write down a position operator for each oscillator \hat{X}_i, where the kernel symbol \hat{X} measures oscillator i's displacement. Likewise, we can write down a "momentum" operator \hat{P}_i which is associated with the rate at which the displacement of oscillator i is changing (i.e. velocity, or more properly, conjugate momentum).
Our notation is nonstandard: in literature the subscript i is traded out for a more descriptive space argument \mathbf{x}, and the kernel symbol denoting the oscillator displacement is usually written \hat\phi or \hat{A}, depending on the field one is talking about. One usually writes \hat{A}(\mathbf{x}) to refer to the operator that is associated with displacement of the quantum oscillator at point \mathbf{x}, and is called the
field operator.
Ray said:
... nor can I see what quantities become probabalistic (e.g. an electroSTATIC field!).
Our picture now is a large collection of
quantum oscillators whose collective displacements are uncertain. However, the interpretation that oscillator displacements correspond to nonvanishing field strengths remains unchanged in moving to quantum mechanics. Therefore we must conclude that field strength values at every point in space is subject to quantum uncertainty. This means, for example, that the value of the electrostatic field in the vicinity of an electron can no longer be specified with complete uncertainty, as suggested by merely using Coulomb's law to infer it (of course, one could do this at the expense of completely loosing information of the field's velocity).
Ray said:
But having converted the normal co-ordinates of the vector potential to operators, I just do not know what they operate on, nor what eigenfunctions they generate...
Eigenstates of the field operator \hat{A}(\mathbf{x}) can be understood to be eigenstates of the displacement operators for all the oscillators: they are states of definite field configurations.