ireland01
- 17
- 0
Fx = sin [ 90 - theta ] * [ dX - [tan (theta) * dY ] ]
??
??
dalcde said:Do you mean
f(x)=\sin(90-\theta)[dX-(tan\theta)dY]
or what? I don't really understand what you wrote.
uart said:Without trying to interpret exactly what Fx, dX or dY denote the simple answer is yes, there are two obvious trigonometric simplifications that result in:
\mbox{Fx} = \cos(\theta) \, dX - \sin(\theta) \, dY
And, by the way, it was the right side of the equation that was simplified, not the left side.ireland01 said:Yes. I mean variables are arbitrary. I just want to know if the left side of the eqn can be simplified at all.
HallsofIvy said:And, by the way, it was the right side of the equation that was simplified, not the left side.