Can I Convert Volts to Electron Volts in Photoelectric Effect Calculations?

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In the discussion, a user is trying to solve a photoelectric effect problem involving the calculation of incident light frequency, given a potential of 3V and a work function. They express confusion over unit conversions, specifically between volts (V) and electron volts (eV), noting that volts measure potential, while electron volts measure energy. The key equation used is Emax = hfinc - φ, where Emax represents the kinetic energy of a photoelectron. It is clarified that to convert volts to electron volts, one can multiply by the charge of an electron (e), establishing a relationship between electric potential and energy. Understanding this conversion is essential for correctly applying the photoelectric effect equations.
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Homework Statement


HI, I have this photoelectric effect problem, it is not so difficult but when i got to the units and red about it , i got confused.
The Problem : Photo-electrons are completely hold up by electric potential with potential of 3V. The work function is given. I have to calculate the incident light frequency.

Homework Equations

The Attempt at a Solution


So the equation is
Emax=hfinc

And the units are
[V]=[J]-[J]
This does not work. So I thought let's convert them to eV which is possible for [J].
But when I start to think about the V -> eV its gets confusing because V are not measurement of energy but eV are.

So what do you think guys, can I just do the conversion from [v] to [ev] by multiplying V by e or it is wrong?
 
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Emax does not denote the stopping potential, but the kinetic energy of a photoelectron. You need to find the relationship between electric potential and energy of a charge in a field.
 
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