Thats my simple question!
IR does not penetrate below 1cm
... not "wrong," into a "semantic ditch," perhaps. If you're going to give me all the solar radiation that penetrates further than 1 mm by the Kebes plot (shorter than 2 μm), you've given me 80 - 90% of the IR. If you define IR as only that radiation that is absorbed in 1 mm or less, and ignore the 0.8 - 2 μm gap between visible and IR acknowledged by a specific argument, you're losing a lot of energy.Where am I going
Not being "flip" with you --- just wanted to be sure we're both working from the same initial set of ideas/postulates/principles.Heat moves from hot to cold obviously.
Welcome to the wonderful world of energy "balances" in non-equilibrium systems. The system we're "analyzing" (hah!) has as heat sources the sun, ~ 10-4steradians at ~ 5800 K or 1-1.3 kW/m2 at earth surface, and crustal heat leak of 10-30 mW/m2, negligible. The heat sink is 4π steradians at ~ 4 K, the CMB. What else do we know? Some fraction of incident solar radiation is reflected, what fraction is subject to some uncertainty; some fraction is transmitted, very small through the atmospheric "halo", but enough to illuminate an otherwise totally eclipsed moon; and, some fraction is absorbed by atmo-, hydro-, and lithospheres, exchanged by conduction, convection, and radiation, and radiated to the CMB.And quite frankly I'm confused!