Can Power Absorbed by 5G1 be 0 in this Circuit?

  • Thread starter Thread starter EvLer
  • Start date Start date
  • Tags Tags
    Circuit Power
AI Thread Summary
In the discussed circuit, the question revolves around whether the power absorbed by the component 5G1 can be zero if the voltage at node N equals the voltage of the ideal voltage source. It is suggested that if the node voltage matches the ideal source voltage, it effectively creates a short circuit between two points. This condition implies that there would be no detectable internal resistance, leading to no energy loss. Therefore, it is concluded that under these circumstances, it is indeed possible for the power absorbed by 5G1 to be zero. The analysis hinges on the relationship between node voltage and the ideal voltage source.
EvLer
Messages
454
Reaction score
0
Hi all,
I have a question on nodal analysis,
if I have the following part of a circuit
Code:
I -->
-G1-------N----5G1-----
          |            |+
         G1          ideal volt source
          |            |-

 G    R    O    U     N   D

Is it possible that power absorbed by 5G1 is 0, i.e. voltage on the node N = voltage of the ideal voltage source? That's what I have, and not sure that it's possible. Thanks in advance.
 
Last edited:
Physics news on Phys.org
When the voltage at the node n=the ideal voltage source, it looks like a short between tow points to me. A short, if the internal resistance is undetectable, then there is no energy loss which I will say it is possible for 5G1=0.
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top