Can Schrodinger's Equation be Transformed into Spherical Polar Coordinates?

asdf1
Messages
734
Reaction score
0
how do you change the schrodinger's equation into the spherical polar coordinates?
 
Physics news on Phys.org
Look up the chain rule for partial derivatives, and the equations that give you x, y, z in terms of r, \theta, \phi for spherical coordinates. Use these to re-write the derivatives \partial^2 \psi / \partial x^2 etc. into the derivatives \partial^2 \psi / \partial r^2 etc. There's a lot of algebra. The final result (which you should be able to see in your textbook) contains both first- and second-order derivatives.
 
Last edited:
The coordinate-free form of the S.E. is:

i\hbar\frac{\partial \Psi(\vec r,t)}{\partial t}=-\frac{\hbar^2}{2m}\nabla^2 \Psi(\vec r,t)+V\Psi(\vec r,t)

You can (should) look up the laplacian operator \nabla^2 in various coordinate systems in your textbook. There's not much physics to be learned by deriving it.
 
thank you very much! :)
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top