Can somebody help me get started on this problem?

  • Thread starter Thread starter cbs81
  • Start date Start date
AI Thread Summary
To determine the direction of vector b in radians counterclockwise from the positive x-axis, the correct approach involves using the arctangent function. The angle can be calculated using the formula tan^-1(-43.8/89.9), which gives the angle in the correct quadrant. Since the angle is measured counterclockwise, adjustments may be needed based on the vector's position relative to the axes. The discussion emphasizes understanding the trigonometric setup and the significance of the counterclockwise measurement. Properly applying these concepts will lead to the correct angle in radians.
cbs81
Messages
3
Reaction score
0
vector b = (89.9)x + (-43.8)y

what is the direction of b in radians counter clockwise from the positive x - axis.

i already solved for the unknown side, but i don't understand how i solve this with the information given? any help would greatly appreciated.
 
Physics news on Phys.org
sorry mods, please move to coursework help.
 
Setup a trig ratio to find the angle in radians...
 
so, do i do:

360 * tan ^-1 (43.8/89.9)

i'm not sure what do about counter clockwise thanks.
 
Last edited:
The counter-clockwise means that if the angle opens below the positive x-axis, then it is considered positive.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

A particle moving in a parabolic path in the ##x-y## plane
Replies
40
Views
2K
Electromagnetism question -- Forces between two current carrying wires
Replies
7
Views
3K
Perpendicular forces acting in x and y directions
Replies
8
Views
2K
Force of the Ladder on a Wall Torque
Replies
5
Views
3K
Particle in equilibrium (balancing forces on an object on an incline)
Replies
5
Views
2K
Stretched spring attached to the center of a pure rolling disk
Replies
11
Views
1K
Can A Vector Have Components Of Say Y or Z in the X-Hat Direction?
Replies
8
Views
904
Calculation of Ramp Jump Distance Using Projectile Motion Formulas?
Replies
12
Views
1K
Net Displacement: Calculate x,y & r,θ
Replies
7
Views
3K
Is it possible to solve relative velocity problems without sine law?
Replies
25
Views
2K

Hot Threads

Recent Insights

Back
Top