- #1
jinman
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I don't understand how to do equilibrium problems. I don't know how to set them up and where to start. here is an example. Can anyone please help?
A uniform thin rod of length 0.50m and mass 4.0 kg can rotate in a horizontal plane about a vertical axis through its center. The rod is at rest when a 3.0g bullet traveling in the rotation plane is fired into one end of the bullet's path makes angle = 60.0 degrees with the rod. If the bullet lodges into the and the angular velocity of the rod is 10 rad/s immediately after the collision, what is the bullet's speed just before impact.
1/2mv^2=1/2Iw^2
I=1/12ML^2
K-initial=K-final
1/2mv^2=1/2Iw^2
solve for v>>>>
v=sq. root[Iw^2/m]
v=sq. root[(1/12*ML^2)w^2/m]
v=sq.root.[(1/12*4.003*.50^2)*10^2/.003]
v=52.7m/s
The answer is 1.3*10^3m/s.
Homework Statement
A uniform thin rod of length 0.50m and mass 4.0 kg can rotate in a horizontal plane about a vertical axis through its center. The rod is at rest when a 3.0g bullet traveling in the rotation plane is fired into one end of the bullet's path makes angle = 60.0 degrees with the rod. If the bullet lodges into the and the angular velocity of the rod is 10 rad/s immediately after the collision, what is the bullet's speed just before impact.
Homework Equations
1/2mv^2=1/2Iw^2
I=1/12ML^2
The Attempt at a Solution
K-initial=K-final
1/2mv^2=1/2Iw^2
solve for v>>>>
v=sq. root[Iw^2/m]
v=sq. root[(1/12*ML^2)w^2/m]
v=sq.root.[(1/12*4.003*.50^2)*10^2/.003]
v=52.7m/s
The answer is 1.3*10^3m/s.