Can someone just lead me in the right direction please

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To determine the angle at which the football was kicked, the initial speed of 22 m/s is split into vertical and horizontal components using trigonometric functions. The horizontal distance of 45 meters is achieved through uniform motion, allowing the equation 45 = 22 Cos(theta) * t to be used. The vertical motion is analyzed with the equation 0 = 22 Sin(theta) - 9.8*t1, where t1 represents the time to reach the highest point. The total time of flight is twice the time to reach the peak, leading to the final equations needed to solve for both the angle and the total time in the air. This analysis combines projectile motion principles to find the required parameters.
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1. A football is kicked with an initial speed of 22m/s at some angle above the horizontal. It travels 45 meters horizontally before hitting the ground.
a. At what angle was the ball initially kicked?
b. How long does it stay in the air?
 
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Split the 22m/s into vertical ( Vy = 22*sin theta) and horizontal components
(Vx =22*Cos theta). Now use the fact that Vy at the highest pt is 0.(use 0 = 22 sin theta - 9.8*t1).
also since motion in the horizontal direction is uniform motion
45 = 22 Cos theta / t.
Also the time taken to reach the highest pt. is half the time taken to reach the ground. ==> t = 2*t1.
 
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