Can This Integral Be Solved Using Factoring and Substitution?

whatlifeforme
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Homework Statement


evaluate the integral.

Homework Equations


\displaystyle\int {\frac{3x+2}{\sqrt{1-x^2}} dx}

The Attempt at a Solution


- i tried factoring hoping for a perfect square that i could take the square root of, but that doesn't work.

-u-sub won't work: u=1-x^2 ; du=2x

-i don't know how to use that denominator in partial fractions.
 
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whatlifeforme said:

Homework Statement


evaluate the integral.

Homework Equations


\displaystyle\int {\frac{3x+2}{\sqrt{1-x^2}} dx}

The Attempt at a Solution


- i tried factoring hoping for a perfect square that i could take the square root of, but that doesn't work.

-u-sub won't work: u=1-x^2 ; du=2x

Break it up into two:##\int\frac{3x}{\sqrt{1-x^2}}dx + \int\frac{2}{\sqrt{1-x^2}}dx##.

Observe that ##3x = -\frac{3}{2}*(-2x)##, and now you should be able to make an obvious sub to resolve the first integral.

For the second integral, just make a simple trig sub.

Partial fractions wouldn't work here because of that square root in the denominator.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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