Can Two Identical Batteries Power Two Bulbs as Brightly as One?

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Two identical batteries can power two bulbs in series, but the brightness will not be the same as one bulb powered by one battery. In a series circuit, the current remains constant throughout, meaning each bulb in the two-bulb setup will receive the same current as the single bulb setup. However, the voltage drop across each bulb must be considered, as each bulb will drop 1.5V, leading to a total of 3V across both in the first scenario. Therefore, while the current is the same, the total voltage and resistance in the circuit affect the overall brightness. The discussion highlights the importance of understanding voltage drops and current flow in series circuits.
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Hello.
Here is my question: Is it possible to connect 2 identical batteries to make 2 bulbs connected in series light just as brightly as one bulb connected to one battery?

Reasoning: let's say each battery has a voltage of 1.5V and that each light bulb is equal and has a resistance of 4 ohms.
Now in circuit 1, with two identical batteries and bulbs, the current flowing through the circuit would I = (1.5V+1.5V) / (4ohms+4ohms) = .38 A
Now in circuit 2, with one battery and bulb, the current flowing through the circuit would be I = (1.5V) / (4ohms) = .38A

We know that the amount of current flowing through a light bulb determines its brightness, and thus in circuit 2, .38 A is flowing through 2 bulbs, and in circuit 1 the same amount of current is flowing through only 1 light bulb, thus it is not possible,

Can someone tell me if this is right? Much appreciated.
 
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Current is continuous through all parts of a series circuit. Consider two bulbs in series: if one bulb has 0.38 A flowing through it, the other must also.

Consider electrons in a wire to behave much like water in a pipe. If some volume of water is flowing through part of a pipe every second, the same volume must be flowing through every other part of the pipe every second.

In the case of (1 bulb, one battery), the bulb drops 1.5V and carries 0.38A of current. In the case of (2 bulbs, 2 batteries), each bulb drops 1.5V and carries 0.38A. Each of those two bulbs would be lit identically to the single bulb, single battery situation.

- Warren
 
I think it also depends on what the voltage drop across each bulb (resistor) is.
 
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