I Can we determine the one way speed of light by combined measurements?

  • #51
HansH said:
But assuming flat space without mass nearby and no moving persons etc, do we than still need a metirc tensor making things different?
Yes.

Let's say I am at the origin, you are at (1,1). How far apart are we? If you say ##\sqrt 2## you are assuming that the coordinates are orthonormal. I could be measuring distance in the x direction in different units from in the y direction - so we could be 1m apart in one direction and 1km apart in the other. I might not have defined my x and y directions as perpendicular, in which case we could be almost 2 units apart or almost zero (assuming I'm using the same distance units this time) depending on whether my axis directions are almost parallel or almost anti-parallel. The metric tensor is what deals with all of this and makes the answers consistent.

If you are using non-orthogonal and possibly unnormalised coordinates (which you are if you are considering a non-isotropic speed of light), you need to account for that in your maths. You don't appear to be doing this, so you are implicitly using orthonormal coordinates, which means that you are implicitly assuming an isotropic speed of light. That's why your answer is that the speed of light must be isotropic - because you assumed it.
 
  • Like
Likes cianfa72
Physics news on Phys.org
  • #52
Ibix said:
Yes.
so If I understand you right you say that at using the normal coordinates we are used to in daily life that then the one way speed of light is always c?
 
  • #53
Choosing to use orthonormal coordinates on spacetime (not just space) is the same as choosing that the one way speed of light is isotropic, yes.

If you want to consider non-isotropic speeds of light you have chosen to consider non-orthonormal coordinates, and you need to factor the implications of that into your maths.
 
  • #54
ok thanks, but that means that what I wanted to proof is already a given fact. My assumption was that the one way speed of light could have different values depending on the synchronisation of your clocks. That was at least my understanding from this movie:
 
  • #55
HansH said:
But assuming flat space without mass nearby and no moving persons etc, do we than still need a metirc tensor making things different?
This doesn't have anything to do with curved spacetime and gravitation. It is just that the math that is used in GR makes this issue very clear, almost trivial. In GR, the math is designed so that one can write the laws of physics in a form where it is clear that the laws of physics are independent of the choice of coordinates. For example, in this form we can write Maxwell's equations as ##\partial^2 A^\sigma=\mu_0 J^\sigma## where ##A## is the four-potential in the Lorenz gauge and ##J## is the four-current density. This form of Maxwell's equations holds in Cartesian coordinates, in polar coordinates, in accelerating reference frames, and in any set of coordinates whatsoever.

Importantly, when expressing the laws of physics in this manner, called "manifestly covariant", the outcome of any physical measurement is also manifestly covariant. Meaning that the outcome of any experiment is independent of the coordinates.

So, if we start with standard Einstein-synchronized coordinates ##(t,x,y,z)## we know that the one-way speed of light is ##c##. We can then make the following coordinate transformation without changing the result of any physical measurement since they are manifestly covariant: $$t \rightarrow T + \kappa X$$ $$x \rightarrow X$$ $$y \rightarrow Y$$ $$z \rightarrow Z$$
Now, this coordinate transformation changes the one-way speed of light and makes it anisotropic. But, since our laws of physics and our experimental results are all manifestly covariant, it does not change any experimental result. Meaning that any result predicted by the isotropic one way speed of light is also predicted by the non-isotropic one-way speed of light.
 
  • Like
  • Informative
Likes Grinkle, cianfa72, HansH and 2 others
  • #56
HansH said:
ok thanks, but that means that what I wanted to proof is already a given fact. My assumption was that the one way speed of light could have different values depending on the synchronisation of your clocks.
So... you already know it's impossible to measure the one way speed of light, so you know your device gives the same output whatever you assume about the one way speed of light. So what was the point of this thread?
 
  • Like
Likes Dale
  • #57
The point was that I thought I had a method to determine the 1 way speed of light as I discribed, but it turned out there was a bug in my reasoning because the 2 almost parallel lines that I proposed are not exacly parallel and therefore still cancel out the effect I wanted to measure. but now there are some residual related items left where the discussion is about.
 
  • #58
HansH said:
The point was that I thought I had a method to determine the 1 way speed of light as I discribed, but it turned out there was a bug in my reasoning because the 2 almost parallel lines that I proposed are not exacly parallel and therefore still cancel out the effect I wanted to measure. but now there are some residual related items left where the discussion is about.
You can perhaps learn something from this line of enquiry, but if you understand relativistc spacetime then you must realize that any scheme to measure a definitive one-way speed must have a flaw in it. You might like to try to prove that are finitely many prime numbers but you must know from the outset that any such proof must have a hidden flaw.
 
  • Like
Likes cianfa72
  • #59
Dale said:
This doesn't have anything to do with curved spacetime and gravitation.

So, if we start with standard Einstein-synchronized coordinates ##(t,x,y,z)## we know that the one-way speed of light is ##c##.
Standard Einstein-synchronized means that you assume c back and forth to syncronize your clock as I understood.
so then am I right that the one way speed of light as presented in this movie can still be anything between c/2 and infinite ? but that then seems to be in contradiction with the remark of Ibix in #54 ?
'Choosing to use orthonormal coordinates on spacetime (not just space) is the same as choosing that the one way speed of light is isotropic, yes.'
 
  • #60
HansH said:
but that then seems to be in contradiction with the remark of Ibix in #54 ?
'Choosing to use orthonormal coordinates on spacetime (not just space) is the same as choosing that the one way speed of light is isotropic, yes.'
That's not a contradiction. It's exactly what I said. Using Einstein synchronised clocks is using orthonormal coordinates and you have an isotropic speed of light. If you don't Einstein synchronise your clocks you aren't using orthonormal coordinates and you don't have an isotropic speed of light.
 
  • Like
Likes PeroK
  • #61
Ibix said:
That's not a contradiction. It's exactly what I said. Using Einstein synchronised clocks is using orthonormal coordinates and you have an isotropic speed of light. If you don't Einstein synchronise your clocks you aren't using orthonormal coordinates and you don't have an isotropic speed of light.
so to get things clear: do you then say that in that movie the one way speed of light is always c (that is what I thought isotropic speed of light means). in the move I don't see they don't talk specifically about ways to choose coordinates so I think they use standard orthonormal coordinates everyone uses in daily life.
 
  • #62
I haven't watched the movie so I've no idea what their argument is. As I have already said, if they are considering anisotropic one way speeds of light then they are considering non-orthonormal coordinate systems - whether they choose to say so explicitly or not.
 
  • #63
HansH said:
am I right that the one way speed of light as presented in this movie can still be anything between c/2 and infinite ?
Yes. I may have understood your position incorrectly. I thought that your position was that the one way speed must be c.

HansH said:
but that then seems to be in contradiction with the remark of Ibix in #54 ?
'Choosing to use orthonormal coordinates on spacetime (not just space) is the same as choosing that the one way speed of light is isotropic, yes.'
That is not in conflict. @Ibix is correct

HansH said:
in the move I don't see they don't talk specifically about ways to choose coordinates so I think they use standard orthonormal coordinates everyone uses in daily life
Since the standard coordinates have the isotropic one way speed of light, and since they are discussing coordinates with non-isotropic one way speeds of light, it is clear that they are using non-standard coordinates. Even if they don’t talk about it explicitly.

By the way, this is why even correct videos are not as effective as a good textbook.
 
  • Like
Likes cianfa72
  • #64
Ibix said:
Using Einstein synchronised clocks is using orthonormal coordinates and you have an isotropic speed of light. If you don't Einstein synchronise your clocks you aren't using orthonormal coordinates and you don't have an isotropic speed of light.
In this discussion we have been assuming a flat spacetime so we are really talking about SR and not the general case of GR.
 
  • #65
Dale said:
Yes. I may have understood your position incorrectly. I thought that your position was that the one way speed must be c.
no so far I saw no reason why it cannot be an arbitrary value between c/2 and infinite. However writing down the equations and generating the graphs as I posted here: https://www.physicsforums.com/threa...by-combined-measurements.1014053/post-6620171

, I realized that the requirements that resulted in these graphs are in my opinion not compatible with the other requirement that the 2 way speed of light must be c in every directon. (because that is a given fact) it could of course be that I made a mistake somewhere but otherwise my conclusion is that due to this compatibility issue the only option left is that the one way speed of light is also c in every direction. as said I will first give some room to our dutch forum to find a potential problem in my reasoning. but later I will post this probably as a new topic (if not clear yet then) as it is not directly related to the proposal that this topic is about.
 
  • #66
cianfa72 said:
In this discussion we have been assuming a flat spacetime so we are really talking about SR and not the general case of GR.
I don't think I've said otherwise.
HansH said:
no so far I saw no reason why it cannot be an arbitrary value between c/2 and infinite.
It can be.
 
  • Like
Likes cianfa72
  • #67
Vanadium 50 said:
There is no one-way speed of light. Sorry to disappoint.

maybe you have 99 equations in 100 uniknowns. Same problem.
At this moment it is the other way around. describing the idea of 1 way lightspeed in a 2d situation I have more equations than variables and therefore a contradicton. so based on that I con only draw the conclusion that light cannot have a 1 way speed depending on direction for a 2 or 3 dimensional world, so if that is not what the physics world derived, then something should be wrong in my assumptions.
 
  • #68
Vanadium 50 said:
Such a material could be used to build a perpetual motion machine. So no.
Would you explain how? I am not familiar with this one.
 
  • #69
HansH said:
then something should be wrong in my assumptions.
...as we have been telling you for some time now.

Let's do this properly. See the diagram in post #1. In the usual Einstein coordinates we describe light leaving S, traveling to A or B, and being reflected to R.

The light leaves S at ##x=0##, ##y=0##, ##t=0##.
It arrives at A/B at ##x=\pm X##, ##y=0##, ##t=X/c##.
It arrives at R at ##x=0##, ##y=Y##, ##t=X/c+(X/\cos\alpha)/c=\frac Xc(1+\sec\alpha)##.

Now let's work in a frame where the speed of light is not isotropic. To do this, we simply apply the coordinate transform ##x'=x##, ##y'=y##, ##t'=t+\kappa x##, where ##\kappa## is a constant with dimensions of inverse velocity and ##|\kappa|<\frac 1c## so that our spatial planes remain spacelike.

The light leaves S at ##x'=0##, ##y'=0##, ##t'=0##.
It arrives at A/B at ##x'=\pm X##, ##y'=0##, ##t'=X/c\pm\kappa X##.
It arrives at R at ##x'=0##, ##y'=Y##, ##t'=\frac Xc(1+\sec\alpha)##.

Note that the only actual difference from the Einstein case is the arrival time of the light at A and B.

From this we can deduce the speed of light along AR and BR. The distance traveled is ##X\sec\alpha## and the time taken is ##\frac Xc(1+\sec\alpha)-(X/c\pm\kappa X)## (i.e., the arrival time at R minus the arrival time at A/B), so the speed is $$c_\pm=\frac{c}{1\mp \kappa c\cos\alpha}$$There are a few interesting cases. First, if ##\kappa=0## this clearly reduces to the isotropic case. Second, if ##\alpha=0## then AR and BR are antiparallel and we have a 1d problem in which we get ##c_\pm=c/(1\mp\kappa c)##. It's easy to see that the average speed, ##c_{av}##, satisfies ##\frac{2X}{c_{av}}=\frac{X}{c_+}+\frac{X}{c_-}##, and hence that ##c_{av}=c## for all ##\kappa## - i.e. that the two-way speed of light is preserved.

If you get different equations from these you are doing something wrong.
 
Last edited:
  • Like
Likes Dale
  • #70
HansH said:
then something should be wrong in my assumptions.
And if that's still the case after 70 posts, then perhaps you need to rethink your approach to learning physics?
 
  • Like
Likes Vanadium 50
  • #71
HansH said:
so far I saw no reason why it cannot be an arbitrary value between c/2 and infinite. … the only option left is that the one way speed of light is also c in every direction
You are contradicting yourself.

As I showed above it is almost trivial to show the conventionality of the one way speed of light.
 
  • #72
Ibix said:
...as we have been telling you for some time now.

Let's do this properly. See the diagram in post #1. In the usual Einstein coordinates we describe light leaving S,

If you get different equations from these you are doing something wrong.
You refer to my post #01 while I already posted an updated version based on what I learned in the meantime, see https://www.physicsforums.com/threa...by-combined-measurements.1014053/post-6620171 leading to a different conclusion probably in line with what you state, but I need to dive into that first. so the discussion about the idea of post #1 is solved already Isuppose.
 

Attachments

  • Image5.gif
    Image5.gif
    96.8 KB · Views: 121
  • #73
Dale said:
You are contradicting yourself.

As I showed above it is almost trivial to show the conventionality of the one way speed of light.
Right if you put these 2 sentences after each other. But the first one was before my further analysis and the second was after, so I had to change my point of view between the first end second line. (which analysis is not yet presented yet) as said I will post this in a separate topic (If I am allowed) as I assume this current topic as clear now and allowed to close.
 
  • #74
Ibix said:
If you are implicitly assuming a diagonal metric, this is equivalent to assuming an isotropic speed of light.
Yes, since starting from the expression of the metric and setting ##ds^2=0## we get a quadratic equation for the coordinate speed of light ##v##. Now in order to get two equal and opposite solutions for the one-way speed of light (one for direction) the mixed term in the equation (i.e. the linear term in ##v##) must vanish (i.e. the metric is diagonal).
 
Last edited:
  • #75
HansH said:
But the first one was before my further analysis and the second was after
Ok, that clarifies. Your first one was correct. Your further analysis has taken you from a correct “before” to an incorrect “after”.

HansH said:
I will post this in a separate topic
There is no point in posting your analysis, I would recommend against it. It would be much better for you to actually learn the correct analyses that have been presented here. The correct analysis is almost trivial to understand, so please start there.
 
  • #76
PeroK said:
And if that's still the case after 70 posts, then perhaps you need to rethink your approach to learning physics?
to be clear: I am not a physics student, but an electrical engineer with a profession in a big semiconductor company as architect in integrated circuit design and systems with 35+ year experience. I do physics for hobby and hope to use this forum to learn with a steep learning curve and get answers on things I do probably wrong as this allows for such a fast learning curve. This could also cause my view to change in time. Hope that is not too much asked? something should be wrong in my assumptions could therefore also mean my latest assumptions, so not the assumptions of 70 posts ago.
 
  • #77
HansH said:
an electrical engineer with a profession in a big semiconductor company as architect in integrated circuit design and systems with 35+ year experience. I do physics for hobby
Cool! I am also an engineer doing physics as a hobby.

You will still be better off focusing on learning the correct concepts and not on dissecting your mistakes.
 
  • Like
Likes PeroK
  • #78
Dale said:
Cool! I am also an engineer doing physics as a hobby.

You will still be better off focusing on learning the correct concepts and not on dissecting your mistakes.
yes of course. But to do that I need to do a university study physics I suppose. learning from books and the internet turned out not to be a very steep curve so far. and engineering is also very challenging. but that is offtopic. So I hope this forum helps a bit.
 
  • #79
HansH said:
But to do that I need to do a university study physics I suppose
I didn’t need to. I did engineering type physics in college, and then the rest has been online. I do use Mathematica a lot and actually frequently work out problems that people post even if I don’t post my answer. I think that is the main thing for me.

The issue with learning the correct concept instead of focusing on dissecting your argument is psychological. A mind abhors a vacuum. If we help poke a hole in your arguments and you don’t understand the correct concept, then that will make a mental vacuum. You will have an empty place where you used to think you knew something, and nothing to fill it. That will make you very reluctant to actually discard the incorrect concept.

In contrast, if you learn the correct concept then you will be able to see the hole in your own argument and since you will already be able to fill it you will not have trouble discarding the incorrect concept.
 
  • #80
Dale said:
Ok, that clarifies. Your first one was correct. Your further analysis has taken you from a correct “before” to an incorrect “after”.

There is no point in posting your analysis, I would recommend against it. It would be much better for you to actually learn the correct analyses that have been presented here. The correct analysis is almost trivial to understand, so please start there.
Ok I will do in a few days as said. I think there is an interesting point of view in this analysis that could be revolutionary or stupid, so could help to make a big step for me or for physics. (I suppose it is for me) I am also waiting for valuable FB from the Dutch forum, so therefore it can take a few days.
 
  • #81
HansH said:
You refer to my post #01 while I already posted an updated version based on what I learned in the meantime, see https://www.physicsforums.com/threa...by-combined-measurements.1014053/post-6620171 leading to a different conclusion probably in line with what you state, but I need to dive into that first. so the discussion about the idea of post #1 is solved already Isuppose.
what you describe is indeed what I also did in the udated version as far as I can see. https://www.physicsforums.com/threa...by-combined-measurements.1014053/post-6620171
so that should not be a point of discussion anymore. Basically it says that the time you gain in 1 direction due to the 1 direction light speed you loose in another direction such that it does not make a difference which path you take or which one way light speed you take, you always get the same 2 way light speed for a certain total pathlength followed. My point is still that I think i have reason to believe that the options for selecting a 1 way light speed are very limited. But I will start a new topic for that to prevent confusion. Would be great to get that clear.
 
  • #82
caz said:
Would you explain how?
Consider the limiting case where the speed of light is zero left to right and non-zero right to left. Energy can move to the left but not to the right. So the left side heats up. If the bar starts at temperature T, eventually there is a temperature differential across the bar, which can be used to drive an engine. The energy for that work comes from cooling the bar - you are spontaneously turning heat into work, and that's a thermodynamic no-no.

But that's a side-track. For the reasons I gave, this is equivalent to claiming there is a solution of one equation in two unknowns. That puts it in the same category as the angle trisectors and circle squarers.
 
  • Like
Likes Frabjous
  • #83
HansH said:
to be clear: I am not a physics student, but an electrical engineer with a profession in a big semiconductor company as architect in integrated circuit design and systems with 35+ year experience. I do physics for hobby and hope to use this forum to learn with a steep learning curve and get answers on things I do probably wrong as this allows for such a fast learning curve. This could also cause my view to change in time. Hope that is not too much asked? something should be wrong in my assumptions could therefore also mean my latest assumptions, so not the assumptions of 70 posts ago.
Physics is a hobby for me too. The issue here, IMO, is that you do you not understand the problem with an unambiguous one-way speed measurement because you have not mastered the basics of relativistic spacetime. If you knew the basics, then this problem would be simple.

Not learning the basics allows such problems to remain a tricky puzzle that you can endlessly enjoy.

Those are the two approaches. Starting from the basics alllows you to develop a solid understanding of the subject. Whereas, jumping in with a specific problem allows you to wander about making one false assumption after the other and relying on us to continually tell you when you have gone wrong.
 
  • Like
Likes Ibix
  • #84
Vanadium 50 said:
Consider the limiting case where the speed of light is zero left to right and non-zero right to left. Energy can move to the left but not to the right. So the left side heats up. If the bar starts at temperature T, eventually there is a temperature differential across the bar, which can be used to drive an engine. The energy for that work comes from cooling the bar - you are spontaneously turning heat into work, and that's a thermodynamic no-no.

But that's a side-track. For the reasons I gave, this is equivalent to claiming there is a solution of one equation in two unknowns. That puts it in the same category as the angle trisectors and circle squarers.
But zero is not a possible solution as I understood, because then you cannot meet the requirement for 2 way speed=c as for one side speed is infinite, for the opposite speed then you need at least c/2. so then you should be able to tell something about energy and temperature in relation to this allowed range.
 
  • #85
HansH said:
what you describe is indeed what I also did in the udated version as far as I can see. https://www.physicsforums.com/threa...by-combined-measurements.1014053/post-6620171
so that should not be a point of discussion anymore.

HansH said:
My point is still that I think i have reason to believe that the options for selecting a 1 way light speed are very limited. But I will start a new topic for that to prevent confusion. Would be great to get that clear.
We made a significant progress on the Dutch forum today. In my description I assumed both a degree of freedom for the 1 way light speed in both x and y direction that led to the contradiction making it impossible to fullfill the requirement of 2 way speed of light in opposite direction being c for all directions. I only got a valuable answer for a few directions.
Finally it turned out that there is a relation between 1 way light speed in both x and y direction (as proposed by another menber) in order to fulfill all requirements. changing the speed equation in my calculation showed that now all requirements were fulfilled. so conclusion is that I had introduced one degree of freedom too much and adding an additional relation solved that problem.
 

Attachments

  • #86
Still one final remark as result of another input [1] posted on the dutch forum: What about a laserbeam reflecting back in in a mirror and causing interferencepatterns on the way in between source and mirror. What if the speed in 2 directions would be different? Then I would suppose you get no interference patterns anymore or at least different?. So isn't that a proof that the speed of light must be equal in all directions?
[1] https://www.wetenschapsforum.nl/viewtopic.php?p=1168776#p1168776
 
  • #87
HansH said:
Still one final remark as result of another input [1] posted on the dutch forum: What about a laserbeam reflecting back in in a mirror and causing interferencepatterns on the way in between source and mirror. What if the speed in 2 directions would be different? Then I would suppose you get no interference patterns anymore or at least different?. So isn't that a proof that the speed of light must be equal in all directions?
[1] https://www.wetenschapsforum.nl/viewtopic.php?p=1168776#p1168776
All your arguments are based on the implicit assumption of absolute Newtonian spacetime, where you have absolute global simultaneity.

The only problem with your ideas is that they are incompatible with relativity. They are basically classical ideas, which do not apply in this universe. Even in the Netherlands!
 
  • #88
HansH said:
Then I would suppose you get no interference patterns anymore or at least different?. So isn't that a proof that the speed of light must be equal in all directions?
I think this is now the third time that I have told you that there is no possible experiment that will depend on the one way speed of light. That means no possible measurement or observation of any physical phenomenon will depend on the one way speed of light. I also explained why in terms of the fact that the laws of physics are covariant and can be written in a manifestly covariant form.

This is why it is useless to address all of the different possible wrong scenarios. As long as you only shoot down wrong ideas and don’t learn the right ideas you will continue coming up with other wrong scenarios. The only useful approach is to learn the correct information. I am not sure why you are avoiding that.
 
  • Like
Likes PeroK
  • #89
Dale said:
I think this is now the third time that I have told you that there is no possible experiment that will depend on the one way speed of light. That means no possible measurement or observation of any physical phenomenon will depend on the one way speed of light. I also explained why in terms of the fact that the laws of physics are covariant and can be written in a manifestly covariant form.

This is why it is useless to address all of the different possible wrong scenarios. As long as you only shoot down wrong ideas and don’t learn the right ideas you will continue coming up with other wrong scenarios. The only useful approach is to learn the correct information. I am not sure why you are avoiding that.
Yes I am fully aware that that remarks was made, but difficult to get the consequences for such a situation as a reflected laserbeam, because it looks counterintuitive. So that was for me the reason to ask this question. So now the conclusion probably is that there are no consequences for this laserbeam but I still cannot understand the details of that. So this means I first need to understand the full theory of relativity and how the 1 way speed of light fits into that before coming back with a question at all. So what is then the goal of this forum if people need to know all details first because then no questions are needed anymore of course?
 
  • #90
HansH said:
So isn't that a proof that the speed of light must be equal in all directions?

No. If a one-way speed is isotropic depends on the definition of simultaneity of events at distant locations. Einstein formulated this as follows:

Einstein said:
an observer placed at the mid-point ##M## of the distance ##AB##
...
That light requires the same time to traverse the path ##A\rightarrow M## as for the path ##B\to M## is in reality neither a supposition nor a hypothesis about the physical nature of light, but a stipulation which I can make of my own freewill in order to arrive at a definition of simultaneity.
Source:
https://en.wikisource.org/wiki/Rela..._I#Section_9_-_The_Relativity_of_Simultaneity

You can for example use the primed 4-dimensional reference coordinate system in the following article and get an anisotropic one-way speed of light:
https://www.mathpages.com/home/kmath229/kmath229.htm
 
Last edited:
  • #91
HansH said:
So what is then the goal of this forum if people need to know all details first because then no questions are needed anymore of course?
The basics are important. It's like asking us to explain a game of chess, but refusing to learn the rules.
 
  • Like
Likes Nugatory and Frabjous
  • #92
HansH said:
it looks counterintuitive. So that was for me the reason to ask this question. So now the conclusion probably is that there are no consequences for this laserbeam but I still cannot understand the details of that
The reason it is counterintuitive is because you don’t understand the right fundamental concepts. The details are not relevant once the underlying principles are understood. There are two important concepts:

1) the laws of physics and the outcomes of all physical experiments are independent of the coordinate system used. This is called covariance.

2) the one way speed of light is purely an aspect of your chosen coordinate system. Changing your coordinate system changes the one way speed of light.

Please focus your attention on these two correct concepts. Once you understand them then it will be intuitive.

HansH said:
So this means I first need to understand the full theory of relativity and how the 1 way speed of light fits into that before coming back with a question at all. So what is then the goal of this forum if people need to know all details first because then no questions are needed anymore of course?
That is a strawman. Nobody said that. We are saying that your approach of “please poke holes in this scenario” is ineffective. That in no way implies that you need to understand everything before coming here with a question. There are many other strategies in between.

What this actually means is that you need to listen to the answers you have received. We have told you that the specific approach you are using is ineffective and we suggested effective approaches. We have explained the correct principles which, if you didn’t understand those explanations, is an invitation to ask follow up questions about those correct principles.

That is what this forum is useful for: asking experts who understand this material and are interested in sharing and then actually using their answers to gain understanding.
 
  • Like
Likes haushofer
  • #93
HansH said:
So this means I first need to understand the full theory of relativity and how the 1 way speed of light fits into that before coming back with a question at all.
No, but it does mean that until you understand the theory you will be unable to construct effective challenges to the predictions of the theory. Sure, you can spend the rest of your life thinking up ever more complicated and creative ways of trying to measure the one-way speed of light - but every one must fail because every one will be a more or less clever way of hiding the same false underlying assumption about absolute simultaneity. This is not an effective way of learning anything, and eventually people will tire of answering questions of the form “I know this can’t work, but tell me where I hid the simultaneity assumption this time?”.

But if instead your questions come from trying to understand the theory, they will be welcome and will receive many helpful answers from the army of unpaid volunteers here who believe that helping people understand physics is a worthy cause.

Edit: @PeroK’s two-sentence response in #92 is the example that I was looking for.
 
  • #94
@ Dale, thanks. This again shines a different light on what I thought 1 way speed of light means. I will digg into your advice first before coming back.

to whom it concerns: The basics depend on your own relative reference. For me that is for sure not general relativity at this moment as I had to keep to other priorities in life which is too short to do all. But I keep being interested.

Of course I do not refuse to learn the rules, but that takes time and will not be done by tomorrow. I realize asking so much questions to speed up the learning curve also asks much of the team. (but your answers help for sure). 90 responses I really appriciate. Thanks for your patience. But perhaps better indeed not to experiment with working out my thoughts to reconstruct the theory and test that with you, because that is not so effective and also costs me a lot of time. That is at least what I also learned from this topic.

For me it remains difficult to grasp the knowledge from the internet or books in a logical order because one first need to now already a lot to be able to determine that logical order needed to be effective.

It is already quite a challenge for example to get clear what is actually meant by 1 way speed of light. (not sure even if I understand that now as I understood first that it was a degree of freedom and it has no effect on what you measure, but based on last input of Dale I should conclude that it is no degree of freedom at all but only 1 on 1 related to your coordinate choice. I think I asked that also several times during the discussions, but still confusing)
 
  • Like
Likes Dale
  • #95
HansH said:
For me that is for sure not general relativity at this moment

For the topic of this thread, basics of SR (flat spacetime) are sufficient. GR (curved spacetime) is not needed.

HansH said:
as I had to keep to other priorities in life which is too short to do all. But I keep being interested. Of course I do not refuse to learn the rules, but that takes time and will not be done by tomorrow.

What you need to understand as basics for the topic are the Einstein clock synchronization and the definition of a standard inertial coordinate system:

Rindler said:
The basic principle of clock synchronization is to ensure that the coordinate description of physics is as symmetric as the physics itself. For example, bullets shot off by the same gun at any point and in any direction should always have the same coordinate velocity dr/dt . Because of the light-postulate, photons serve particularly conveniently as such bullets in SR.
...
We should, strictly speaking, differentiate between an inertial frame and an inertial coordinate system, although in sloppy practice one usually calls both IFs. An inertial frame is simply an infinite set of point particles sitting still in space relative to each other. For stability they could be connected by a lattice of rigid rods, but free-floating particles are preferable, since keeping constant distances from each other is also a criterion of the non-rotation of the frame. A standard inertial coordinate system is any set of Cartesian x,y,z axes laid over such an inertial frame, plus synchronized clocks sitting on all the particles, as described above. Standard coordinates always use identical units, say centimeters and seconds.
Source:
http://www.scholarpedia.org/article...nematics#Galilean_and_Lorentz_transformations
 
  • Like
Likes HansH
  • #96
cianfa72 said:
It is that given an inertial frame if we do a measurement of two-way speed of light the result is always the same regardless of the state of motion of the light source employed w.r.t the given inertial frame.
I would like to discuss further the following point. Consider two light sources, the first (A) at rest and the second (B) moving with constant velocity ##v## w.r.t. a given inertial reference frame. Suppose the two-way speed of light emitted from the stationary source (A) is isotropic with fixed speed ##c##. Then from the principle of relativity it follows that the two-way speed of light emitted from source B measured in the inertial frame in which it is at rest must be isotropic with fixed value ##c## as well.

Note that the principle of relativity does not imply at all that the two-way speed of light as measured in an inertial frame may not depend on the state of motion of the source. So the two-way speed of light emitted from source B measured in the first inertial frame (i.e. the rest frame of source A) might not be isotropic and/or with constant speed ##c##.
 
Last edited:
  • #97
cianfa72 said:
Note that the principle of relativity does not imply at all that the two-way speed of light as measured in an inertial frame may not depend on the state of motion of the source.
But the second postulate of SR implies that the two-way speed of light as measured in an inertial frame does not depend on the state of motion of the source.
 
  • Like
Likes cianfa72
  • #98
Sagittarius A-Star said:
But the second postulate of SR implies that the two-way speed of light as measured in an inertial frame does not depend on the state of motion of the source.
Yes of course, as you said it is the second postulate of SR and it is logically indipendent from the the principle of relativity (the first principle).
 
  • Like
Likes Sagittarius A-Star
  • #99
HansH said:
The basics depend on your own relative reference. For me that is for sure not general relativity
I agree. I apologize if I gave that impression. I was just asking about your background because if you did happen to already know the math of GR (tensors) then the explanation is very easy. But this problem is not itself a GR problem and does not require knowledge of GR.

HansH said:
It is already quite a challenge for example to get clear what is actually meant by 1 way speed of light
When you decide to pursue this topic further, that might be the place to start.
 
  • Like
Likes HansH
  • #100
Sagittarius A-Star said:
But the second postulate of SR implies that the two-way speed of light as measured in an inertial frame does not depend on the state of motion of the source.
Just to highlight that assuming both the first and the second postulate force us to give up galilean transformation between inertial reference frames (i.e. global inertial coordinate charts for flat spacetime) in favour of Lorentz transformations.
 

Similar threads

Replies
42
Views
637
Replies
93
Views
5K
Replies
53
Views
6K
Replies
5
Views
320
Replies
32
Views
2K
Back
Top