Can X-rays Cause Electrons to be Emitted from Gold Foil?

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X-rays can indeed cause electrons to be emitted from gold foil, making option A a valid answer. The discussion clarifies that options C and E are related, as adding a proton would change the element. The user contemplates the possibility of A being the correct choice while dismissing C and E. The focus remains on the emission of electrons as the primary effect of X-ray interaction with gold. Ultimately, the conversation centers on the implications of X-ray exposure on the atomic structure of gold.
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X-rays striking a piece of gold foil may cause:

a. electrons to be emitted
b. isotopes of gold to form
c. addition of protons to gold atoms
d. addition of neutrons to gold atoms
e. nuclear transmutation of gold into another element

I think the answer is a or c. Can someone help me? Thanks.
 
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Consider that C and E are saying basically the same thing; if gold obtained another proton, it would become another element because elements are defined by the number of protons they have.
 
thanks, i will cancel C and E, but could A be a potential answer?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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