Can you multiply this matrix with a singular value?

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SUMMARY

You can multiply a 2x3 matrix with a 3x1 matrix, resulting in a 2x1 matrix. The multiplication is valid when the number of columns in the first matrix equals the number of rows in the second matrix. In this case, the calculations yield the results 57 and -78, which can be represented either vertically or horizontally as [57, -78]. Additionally, it is important to note that the correct singular form of "matrices" is "matrix".

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TonyC
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I understand the number of rows must equal the number of columns to multiply but:

Is it possible to find the product of this matrice?

AB if A= 0...9... -6
... -2...-10...7

B= 7
...5
...-2
 
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Yes, you can multiply a 2x3 matrix with a 3x1 matrix. The result will be a 2x1 matrix.

In general, you can only multiply a axb matrix with cxd matrix if b=c. The result is an axd matrix.
 
Just so I have this straight:
(0)(7) + (9)(5) + (-6)(-2) = 57
(-2)(7) + (-10)(5) + (7)(-2) = -78

written:
57
-78

am I correct?
 
or is it written: [57,-78] ?
 
You can write it either way. Vertically, like you had it. Or horiz. with a T above the right parenthase. That is to indicate it is the transpose.
 
Thank you very much!
 
By the way- the singular of "matrices" is "matrix", not "matrice".
 

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