Can you multiply this matrix with a singular value?

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It is possible to multiply a 2x3 matrix by a 3x1 matrix, resulting in a 2x1 matrix. The multiplication is valid because the number of columns in the first matrix equals the number of rows in the second. The calculations yield results of 57 and -78. The final answer can be represented either vertically as two separate values or horizontally as a single row with a transpose notation. Additionally, the correct singular form of "matrices" is "matrix."
TonyC
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I understand the number of rows must equal the number of columns to multiply but:

Is it possible to find the product of this matrice?

AB if A= 0...9... -6
... -2...-10...7

B= 7
...5
...-2
 
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Yes, you can multiply a 2x3 matrix with a 3x1 matrix. The result will be a 2x1 matrix.

In general, you can only multiply a axb matrix with cxd matrix if b=c. The result is an axd matrix.
 
Just so I have this straight:
(0)(7) + (9)(5) + (-6)(-2) = 57
(-2)(7) + (-10)(5) + (7)(-2) = -78

written:
57
-78

am I correct?
 
or is it written: [57,-78] ?
 
You can write it either way. Vertically, like you had it. Or horiz. with a T above the right parenthase. That is to indicate it is the transpose.
 
Thank you very much!
 
By the way- the singular of "matrices" is "matrix", not "matrice".
 
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