Can you solve a series circuit problem with 3 resistors and a 24V battery?

AI Thread Summary
A circuit with three resistors in series connected to a 24V battery has a current of 32.0 mA. Two resistors are 250.0 Ω and 150.0 Ω, leading to the calculation of the third resistor as 350 Ω. To find the voltage drop across each resistor, Ohm's Law (V = I × R) is applied, using the known current and resistance values. The total voltage across all resistors must equal the battery voltage of 24V. Understanding these calculations clarifies how to determine the voltage drop for each resistor in the circuit.
camel-man
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1.A circuit consists of 3 resistors connected in series to a 24.0 V battery. The current in the circuit is 32.0 mA. If 2 of the resistors are 250.0  and 150.0 ,

find the value of the third resistor.

find the potential difference across each resistor.

2. R=V/I3. I calculated the third resistor to be 350 ohms

I am confused on what this means "find the potential difference across each resistor."

What equation do I use for this?
 
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You know the current through each resistor and you know the resistance for each.
You need the voltage. What equation would you use?
 
Use the term "voltage drop" instead of potential difference, and you'll have the answer. :)
 
nasu said:
You know the current through each resistor and you know the resistance for each.
You need the voltage. What equation would you use?

Isn't the voltage given though at 24 v?
 
camel-man said:
Isn't the voltage given though at 24 v?
Yes, so when you sum the three resistor voltages the result must equal 24V. Determine the separate resistor voltages. Apply Ohm's Law.
 

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