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Canisters Rolling Down a Half Pipe

  1. Nov 21, 2011 #1
    1. The problem statement, all variables and given/known data
    Oddjob rolls a canister of nerve gas twoards Bond, who is at the bottom of a curved trench. The canister has a mass of 16 kg, a radius of r = 0.8 m, and a rotational inertia of 10 kg*m2. It starts with no velocity. If the trench has a radius of R = 3.5 m, how fast is the canister moving when it reaches Bond?

    2. Relevant equations

    Conservation of Energy: Ei = Ef


    3. The attempt at a solution

    PEi = KEf + KErotation
    mgR = (1/2)m*vf2 + (1/2)I*ω2
    mgR = (1/2)m*vf2 + (1/2)I*(vf/R)2
    mgR = vf2 (m/2 +I/(2R2))
    vf2 = (2*m*g*R3) / (m*R2 + I)
    vf = sqrt((2*m*g*R3) / (m*R2 + I))

    I plugged in all the numbers but the computer says this is incorrect. Where did I go wrong?

    Edit: I posted the wrong question initally. Oops. This is the correct one with the correct image.
     

    Attached Files:

    Last edited: Nov 21, 2011
  2. jcsd
  3. Nov 21, 2011 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Is Bond at the bottom of the trench? Or on the opposite side?
     
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