- #1
mujadeo
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Homework Statement
Six point charges, four positive (+q) and two negative (-q), are fixed at thepositions shown (i attached a .gif file --pls tell me if this isn't visable) in the x-y plane; q = 2.1 × 10-6C and a = 0.93 m. A test charge Q = 0.6 × 10-6C is at the origin.
(a) Find the x- and y-components of the total force on Q:
Homework Equations
i successfully calcd the x-component (-.017016N) but can't get the y component
The Attempt at a Solution
heres what i did
1. labelled the charges A thru F starting with the charge on the neg y-axis (A) and the labelled in cw direction.
2. so for y component everything either cancels or has no y-component, EXCEPT for the 2 charges on the y-axis. These are both pos charges.
so here's the calc
Ay = (9*10^9)(2.1*10^-6)(.6*10-6) / (.93^2) = .01311N (pos charge)
Dy = (9*10^9)(2.1*10^-6)(.6*10-6) / (.93^2) = .01311N (also pos charge)
so 2(.01311) = .02622N
this is wrong!
please help!
thanks