Cant get y-component of point charges on test charge

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SUMMARY

The discussion centers on calculating the y-component of the force exerted on a test charge Q by six point charges arranged in the x-y plane. The user successfully calculated the x-component of the force as -0.017016 N but struggled with the y-component. The correct approach involves recognizing that the two positive charges on the y-axis exert equal and opposite forces on Q, resulting in a net y-component of zero. Thus, the user must consider the cancellation of forces from these charges to arrive at the correct conclusion.

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mujadeo
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Homework Statement


Six point charges, four positive (+q) and two negative (-q), are fixed at thepositions shown (i attached a .gif file --pls tell me if this isn't visable) in the x-y plane; q = 2.1 × 10-6C and a = 0.93 m. A test charge Q = 0.6 × 10-6C is at the origin.

(a) Find the x- and y-components of the total force on Q:




Homework Equations


i successfully calcd the x-component (-.017016N) but can't get the y component


The Attempt at a Solution



heres what i did

1. labelled the charges A thru F starting with the charge on the neg y-axis (A) and the labelled in cw direction.

2. so for y component everything either cancels or has no y-component, EXCEPT for the 2 charges on the y-axis. These are both pos charges.
so here's the calc
Ay = (9*10^9)(2.1*10^-6)(.6*10-6) / (.93^2) = .01311N (pos charge)
Dy = (9*10^9)(2.1*10^-6)(.6*10-6) / (.93^2) = .01311N (also pos charge)
so 2(.01311) = .02622N
this is wrong!
please help!
thanks
 

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mujadeo said:
2. so for y component everything either cancels or has no y-component, EXCEPT for the 2 charges on the y-axis.

No. this is wrong. The two charges on the y-axis exert equal but opposite forces on Q, hence they cancel.

Which are the two charges you need to consider?
 

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