Factors Affecting Capacitance in a Capacitor

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Capacitance in a capacitor can be increased by decreasing the distance between the plates, increasing the charge, decreasing the electric field, and increasing the area of the plates, while thickness does not affect capacitance. The equation C = εA/d is more relevant for understanding these factors than Q = CV. A stronger electric field can attract more charges, thus increasing capacitance. Additionally, increasing the dielectric constant (k) will also enhance capacitance. Understanding these principles is crucial for analyzing capacitor behavior in electrical circuits.
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Homework Statement



What will increase the capacitance of a capacitor?

Homework Equations



Q=CV
V = Ed

The Attempt at a Solution



Factors that increase:
-Decrease in distance
-Increase in charge
-Decrease in electric field
-Increase in area (length and width of the capacitor, but its thickness has no affect)

Would these be correct, also what about the dielectric constant (k), would increasing it increase capacitance or decrease it?
 
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Gear2d said:

Homework Statement



What will increase the capacitance of a capacitor?

Homework Equations



Q=CV
V = Ed

The Attempt at a Solution



Factors that increase:
-Decrease in distance
-Increase in charge
-Decrease in electric field
-Increase in area (length and width of the capacitor, but its thickness has no affect)

Would these be correct, also what about the dielectric constant (k), would increasing it increase capacitance or decrease it?

Q = VC is not exactly the right equation to consider. The capacitor is the constant that relates the Charge to Voltage and is not a property of the capacitor per se. If you change the voltage then the charge changes as determined by the C - it is just descriptive of the relationship between Q and V as defined by C..

On the other hand:

C = εA/d would be more to the point of the question.

For more on capacitors read the link - https://www.physicsforums.com/library.php?do=view_item&itemid=112
 


Hello Gear2d, I am Gear300...
Its pretty much what LowlyPion said. C = Q/V is somewhat deceptive. If you think about it, a stronger electric field should bring in more charges...and it does. If you decrease the value of E, then you decrease the value of Q. C is the constant, and what you would want is a more stable equation for it (provided by LowlyPion). If you want to further adjust the equation, then C = εA/d = Q/V = Q/(Ed)...Q = εAE...so charge increases with increasing electric field. Increasing the dielectric constant k increases the capacitance. If you want to know how, look for something correlating with a microscopic observation of capacitance and dielectrics.
 
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