Difference Between Capacitor Equations: q=Q(1-e^-t/RC) & q=Qe^-t/RC

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The discussion clarifies the difference between two capacitor equations: q=Q(1-e^-t/RC) describes a charging capacitor, while q=Qe^-t/RC represents a discharging capacitor. In the first equation, the capacitor starts uncharged, and as time progresses, the charge increases to Q. Conversely, the second equation indicates that the capacitor begins fully charged and discharges over time, decreasing to zero charge. The presence of "1-" in the first equation signifies the transition from an uncharged state to a fully charged state. Understanding these equations is crucial for analyzing capacitor behavior in circuits.
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hey guys, have a quick question

just wanted to know what is the difference between these two equations, i couldn't find anything on google

q=Q(1-e^-t/RC)

and

q=Qe^-t/RC


why does one have 1 subtracting the rest of the equation, and the other doesn't

thanks!
 
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I understand that in the first equation the capacitor is uncharged before the switch is closed, and when the switch is closed at t=0, charge (q) will increase.

I just don't understand what the "1-" has to do with the problem
 
wait i think i got it, in the second equation, the capacitor is charged, and it is discharging.

in the first equation, it is uncharged. is this correct?
 
The second equation is for a series connection of a voltage source, resistor, and a capacitor. Applying KVL around the loop and integrating, that is the result. The case is indeed for a capacitor discharging; hence the exponential decay.
 
Try calculating Q for t=0 and t=∞...

1) q=Q(1-e^-t/RC)

t=0, q=0
t=∞, q=Q
= charging

2) q=Qe^-t/RC

t=0, q=Q
t=∞, q=0
= discharging
 
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