How Do You Solve Capacitor Series Circuit Problems?

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To solve capacitor series circuit problems, the equivalent capacitance (Ceq) can be calculated using the formula 1/Ceq = Σ(1/Ck) for each capacitor in the series. In a series circuit, the charge (Q) on each capacitor is the same, while the voltage across each capacitor can vary. To find the voltage across the first capacitor, use the relationship Q = CV, where C is the capacitance of the first capacitor. Understanding these principles is crucial for solving related problems effectively. Mastery of these concepts is essential for success in capacitor circuit analysis.
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Good day everyone. Please help with these questions.

The circuit is a series of 3 capacitors with a battery.
C1 = C
C2 = 2C
C3 = 3C

How do you find the voltage across the first capacitor in a series of 3?

How do you find the charge Q on the first capacitor?

How do you find the equivalent capacitance Ceq for this combination of capacitors in series?

I had these questions on a test and know the answers but not how to arrive at them. I am usually quick on the uptake but teaching this basic stuff adequately is apparently beneath my professor and the text is terrible! (stay away from Young & Geller!)

Thanks for any help you can provide.
 
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The equivalent capacitance of a series of n capacitors is done by the expression:
\frac{1}{C_{eq}}=\sum_{k=1}^n \frac{1}{C_k}
The charge in all capacitors is the same.
Charge, voltage and capacitance are related by:
q = CV
 
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